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3 years ago

Can someone please shows me the steps and answer. Urgent!

Physics

1 answer:

BabaBlast [244]3 years ago

6 0

Using the formula t=root of 2h/g then where h=28 and g=9.8 then substitute so the answer is 2.4seconds

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Someone please help me, I’m so lost my brain hurts

tiny-mole [99]

-- It takes 100 calories of heat to make 10 grams of the stuff 20° warmer.

How much of the heat warms each gram ?

-- It takes 10 calories of heat to make each gram of the stuff 20° warmer.

How much of the heat warms that gram each degree ?

-- It takes 1/2 calorie of heat to make each gram of the stuff 1° warmer.

The specific heat of that stuff is

(1/2 calorie) per gram per °C.

That's choice-3 .

7 0

3 years ago

Read 2 more answers

A uniform beam with mass M and length L is attached to the wall by a hinge, and supported by a cable. A mass of value 3M is susp

Jobisdone [24]

Answer:

The tension is $T= \frac{11}{2\sqrt{3} } Mg$

The horizontal force provided by hinge $Fx= \frac{11}{4\sqrt{3} } Mg$

Explanation:

From the question we are told that

The mass of the beam is $m_b =M$

The length of the beam is $l = L$

The hanging mass is $m_h = 3M$

The length of the hannging mass is $l_h = \frac{3}{4} l$

The angle the cable makes with the wall is $\theta = 60^o$

The free body diagram of this setup is shown on the first uploaded image

The force $F_x \ \ and \ \ F_y$ are the forces experienced by the beam due to the hinges

Looking at the diagram we ca see that the moment of the force about the fixed end of the beam along both the x-axis and the y- axis is zero

$\sum F =0$

Now about the x-axis the moment is

$F_x -T cos \theta = 0$

=> $F_x = Tcos \theta$

Substituting values

$F_x =T cos (60)$

$F_x= \frac{T}{2} ---(1)$

Now about the y-axis the moment is

$F_y + Tsin \theta = M *g + 3M *g ----(2)$

Now the torque on the system is zero because their is no rotation

So the torque above point 0 is

$M* g * \frac{L}{2} + 3M * g \frac{3L}{2} - T sin(60) * L = 0$

$\frac{Mg}{2} + \frac{9 Mg}{4} - T * \frac{\sqrt{3} }{2} = 0$

$\frac{2Mg + 9Mg}{4} = T * \frac{\sqrt{3} }{2}$

$T = \frac{11Mg}{4} * \frac{2}{\sqrt{3} }$

$T= \frac{11}{2\sqrt{3} } Mg$

The horizontal force provided by the hinge is

$F_x= \frac{T}{2} ---(1)$

Now substituting for T

$F_{x} = \frac{11}{2\sqrt{3} } * \frac{1}{2}$

$Fx= \frac{11}{4\sqrt{3} } Mg$

4 0

3 years ago

2. A 1750 kg car accelerates at a rate of 4.0 m/s2. How much force is the cars engine producing?

8090 [49]

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 1750 × 4

We have the final answer as

Hope this helps you

6 0

3 years ago

If you find two stars with the same Right Ascension, are they necessarily close together in the sky? Why or why not?

shepuryov [24]

In space, spatial coordinates can be roughly divided into measures of Right ascension and declination. The declination is measured in degrees while the ascent is measured in hours, minutes, seconds. When you have objects in space such as those of the characteristics presented we will have to they are not necessarily close together in the sky because we can find two stars on the same right ascension but on different declination lines (Which means they can be very far apart from each other)

8 0

3 years ago

A bowling ball is dropped on a moon from the height of 14 m. The acceleration of gravity on the moon is 4 m/s2. Determine the ti

goblinko [34]

Answer:

4sec

Explanation:

Since we know the initial velocity=0, acceleration = -4; and the displacemnt =14, we use the equation d = vi • t + ½ • a • t2. So, just plug in the values and solve for t in this case it's 4 sec

7 0

3 years ago