I think the answer is ‘repulsion’
Answer:
56.9 mmoles of acetate are required in this buffer
Explanation:
To solve this, we can think in the Henderson Hasselbach equation:
pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])
To make the buffer we know:
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
We know that Ka from acetic acid is: 1.8×10⁻⁵
pKa = - log Ka
pKa = 4.74
We replace data:
5.5 = 4.74 + log ([acetate] / 10 mmol)
5.5 - 4.74 = log ([acetate] / 10 mmol)
0.755 = log ([acetate] / 10 mmol)
10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)
5.69 = ([acetate] / 10 mmol)
5.69 . 10 = [acetate] → 56.9 mmoles
Answer:
The given statement is true.
Enzymes which are present in the digestive tract such as salivary amylase, pepsin, trypsin, et cetera mainly catalyze the hydrolysis reaction.
The hydrolysis reaction is the reaction by which large molecules are broken down into smaller molecules with the help of water.
Most of the complex molecules or nutrients such as starch, protein et cetera are broken down into their respective smaller units with the help of hydrolysis reaction.
For example, lactase catalyzes the hydrolysis of lactose into glucose and galactose.