Answer:
9.36g of H2O.
Explanation:
We'll begin by writing the balanced equation for the reaction.
2Na + 2H2O —> 2NaOH + H2
Next, we shall determine the mass of Na and H2O that reacted from the balanced equation.
This is illustrated below:
Molar mass of Na = 23g/mol
Mass of Na from the balanced equation = 2 x 23 = 46g
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mass of H2O from the balanced equation = 2 x 18 = 36g
From the balanced equation above,
46g of Na reacted with 36g of H2O.
Now, we can determine the mass of H2O involved in reaction as follow:
From the balanced equation above,
46g of Na reacted with 36g of H2O.
Therefore, 11.96g of Na will react with = (11.96 x 36)/46 = 9.36g of H2O.
Therefore, 9.36g of H2O were used for the reaction.
