Answer:
Q = 1379.4 J
Explanation:
Given data:
Mass of water = 22 g
Initial temperature = 18°C
Final temperature = 33°C
Heat absorbed = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 J/g.
°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 33°C - 18 °C
ΔT = 15°C
Q = 522 g ×4.18 J/g.°C× 15°C
Q = 1379.4 J
Answer:
Actually, we can answer the problem even without the first statement. All we have to do is write the reaction for the production of sulfur trioxide.
2 S + 3 O₂ → 2 SO₃
The stoichiometric calculations is as follows:
6 g S * 1 mol/32.06 g S = 0.187 mol S
Moles O₂ needed = 0.187 mol S * 3 mol O₂/2 mol S = 0.2805 mol O₂
Since the molar mas of O₂ is 32 g/mol,
Mass of O₂ needed = 0.2805 mol O₂ * 32 g/mol = 8.976 g O₂
Answer:
its answer A....that's the answer is
Explanation:
The visible light spectrum is the section of the electromagnetic radiation spectrum that is visible to the human eye. Essentially, that equates to the colors the human eye can see. It ranges in wavelength from approximately 400 nanometers (4 x 10 -7 m, which is violet) to 700 nm (7 x 10-7 m, which is red).
Answer:
ΔS°reaction = 100.9 J K⁻¹ (mol C₃H₈)⁻¹
Explanation:
The equation for the reaction is given as;
C₃H₈(g) + 5O₂(g) → 4H₂O(g) + 3CO₂(g)
In order to determine the entropy change, we have to use the entropy valuues for the species in the reaction. This is given as;
S°[C₃H₈(g)] = 269.9 J K⁻¹ mol⁻¹
S°[O₂(g)] = 205.1 J K⁻¹ mol⁻¹
S°[H₂O(g)] = 188.8 J K⁻¹ mol⁻¹
S°[CO₂(g)] = 213.7 J K⁻¹ mol⁻¹
The unit of entropy is J K⁻¹ mol⁻¹
Entropy change for the reaction is given as;
ΔS°reaction = ΔS°product - ΔS°reactant
ΔS°reaction = [(4 * 188.8) + (3 * 213.7)] - [269.9 + (5 * 205.1)]
ΔS°reaction = 100.9 J K⁻¹ (mol C₃H₈)⁻¹
From 30 April 1789 to 4 March 1797
