Answer:
Explanation:
It is given that,
Wavelength of hydrogen line, ![\lambda=656.28\ nm=656.28\times 10^{-9}\ m](https://tex.z-dn.net/?f=%5Clambda%3D656.28%5C%20nm%3D656.28%5Ctimes%2010%5E%7B-9%7D%5C%20m)
Shift in wavelength, ![\lambda'=656.08\ nm=656.08\times 10^{-9}\ m](https://tex.z-dn.net/?f=%5Clambda%27%3D656.08%5C%20nm%3D656.08%5Ctimes%2010%5E%7B-9%7D%5C%20m)
According to Relativistic Doppler Effect, the shift in wavelength is given by :
![\dfrac{\lambda'}{\lambda}=\sqrt{\dfrac{1+v/c}{1-v/c}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Clambda%27%7D%7B%5Clambda%7D%3D%5Csqrt%7B%5Cdfrac%7B1%2Bv%2Fc%7D%7B1-v%2Fc%7D%7D)
v is the speed of star
c is the speed of light
![(\dfrac{\lambda'}{\lambda})^2=\dfrac{c+v}{c-v}](https://tex.z-dn.net/?f=%28%5Cdfrac%7B%5Clambda%27%7D%7B%5Clambda%7D%29%5E2%3D%5Cdfrac%7Bc%2Bv%7D%7Bc-v%7D)
![v=c-\dfrac{2c}{(\dfrac{\lambda'}{\lambda})^2+1}](https://tex.z-dn.net/?f=v%3Dc-%5Cdfrac%7B2c%7D%7B%28%5Cdfrac%7B%5Clambda%27%7D%7B%5Clambda%7D%29%5E2%2B1%7D)
![v=91438.32\ m/s](https://tex.z-dn.net/?f=v%3D91438.32%5C%20m%2Fs)
or
v = 91.43 km/s
So, the star is moving with a speed of about 100 km/s. Hence, this is the required solution.
It is 66.1 :) You multiply all of them together
For the rest 3 km
Bholu need to run in 5 minutes so
He need to 3 × 1000 / 5 × 60 m/s
3000/ 300 = 10 m/s
So , his speed should be 1 m/s to reach in 5 minute
mark as brainliest 5 star
Answer:
47.43 m/s
Explanation:
Given that,
Final speed of a plane, v = 0
Distance, d = 180 m
Acceleration of the plane, a = -6.25 m/s² (deceleration )
We need to find the plane's velocity. Let it was u. So, using the third equation of kinematics as :
![v^2-u^2=2ad\\\\u^2=0^2-2\times (-6.25)\times 180\\\\u=\sqrt{2250} \\\\u=15\sqrt{10}\ m/s\\ \\\text{or}\\\\u=47.43\ m/s](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2ad%5C%5C%5C%5Cu%5E2%3D0%5E2-2%5Ctimes%20%28-6.25%29%5Ctimes%20180%5C%5C%5C%5Cu%3D%5Csqrt%7B2250%7D%20%5C%5C%5C%5Cu%3D15%5Csqrt%7B10%7D%5C%20m%2Fs%5C%5C%20%5C%5C%5Ctext%7Bor%7D%5C%5C%5C%5Cu%3D47.43%5C%20m%2Fs)
So, the plane's velocity when it first touched the landing strip is 47.43 m/s.