Answer:
Explanation:I don't say you must have to mark my ans as brainliest but if you think it has really helped u plz don't forget to thank me....
Given the distance traveled and time elapsed, the average speed of the train is approximately 26.944m/s.
<h3>What is the average speed of the train?</h3>
Speed is simply referred to as distance traveled per unit time.
Mathematically, Speed = Distance ÷ time.
Given the data in the question;
- Distance traveled = 221miles
- Elapsed time = 3 hours and 40 minutes
First we convert miles to meters and Hours minutes to seconds.
221 miles = ( 221 × 1609.344 )m = 355665.024 meters
3 hours and 40 minutes = ( 3×60×60)s + ( 40×60)s
= 10800s + 2400s
= 13200s
Now, determine the average speed.
Speed = Distance ÷ time
Speed = 355665.024m / 13200s
Speed = 26.944m/s
Given the distance traveled and time elapsed, the average speed of the train is approximately 26.944m/s.
Learn more about speed here: brainly.com/question/7359669
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Kinetic Energy is defined by 1/2 times the mass times the velocity squared.
KE = (1/2)mv2
Answer:
Velocity of the car at the bottom of the slope: approximately
.
It would take approximately
for the car to travel from the top of the slope to the bottom.
Explanation:
The time of the travel needs to be found. Hence, make use of the SUVAT equation that does not include time.
- Let
denote the final velocity of the car. - Let
denote the initial velocity of the car. - Let
denote the acceleration of the car. - Let
denote the distance that this car travelled.
.
Given:
Rearrange the equation
and solve for
:
.
Calculate the time required for reaching this speed from
at
:
.
Answer:
it depends on the weight's ratio
(sorry)