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34kurt
3 years ago
9

Using what you know about newton's second law explain why a car with a lager mass use more fuel than a car with a smalle mass. a

ssume both car dreive the same distance
Physics
1 answer:
NNADVOKAT [17]3 years ago
3 0
The car with bigger Mass requires more fuel because More mass the heavier it gets. you can't grab the little car fuel tank and put it in the big car it will run out to fast.

overall answer : The bigger the mass = more weight which means it needs more fuel to run
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A child sits on a merry-go-round, 1.5 meters from the center. The merry-go-round is turning at a constant rate, and the child is
exis [7]

Answer:

5 .07 s .

Explanation:

The child will move on a circle of radius r

r = 1.5 m

Let the velocity of rotation = v

radial acceleration = v² / r

v² / r = 2.3

v² = 2.3 r = 2.3 x 1.5

= 3.45

v = 1.857 m /s

Time of revolution = 2π r / v

= 2 x 3.14 x 1.5 / 1.857

= 5 .07 s .

5 0
3 years ago
If someone throws a 3 gram fry accelerating at 5 meter/second2, what is the fry’s force?
Arada [10]

The force on the fry is 0.015 N

Explanation:

We can find the force acting on the fry by using Newton's second law:

F=ma

where

F is the net force on the fry

m is its mass

a is its acceleration

For the fry in this problem,

m=3 g = 0.003 kg

a=5.0 m/s^2

Therefore, the force exerted on the fry is

F=(0.003)(5)=0.015 N

Learn more about Newton's second law here:

brainly.com/question/3820012

#LearnwithBrainly

3 0
3 years ago
what is the definition of sonic booms? HELP ASAP 50 POINTS !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! and breainliest
Morgarella [4.7K]

Answer:

a loud explosive noise caused by the shock wave from an aircraft traveling faster than the speed of sound.

Explanation:

8 0
3 years ago
Read 2 more answers
The hour, minute, and second hands on a clock are 0.25 m , 0.31 m , and 0.34 m long, respectively.
sp2606 [1]

In 1 hour, the hour hand sweeps across 1/12 of the clock's face. In 40 min, the hour hand travels (40 min)/(60 min) = 2/3 of the path it covers in an hour, so a total of 1/12 × 2/3 = 1/18 of the clock's face. This hand traces out a circle with radius 0.25 m, so in 40 min its tip traces out 1/18 of this circle's radius, or

1/18 × 2<em>π</em> (0.25 m) ≈ 0.087 m

The minute hand traverses (40 min)/(60 min) = 2/3 of the clock's face, so it traces out 2/3 of the circumference of a circle with radius 0.31 m:

2/3 × 2<em>π</em> (0.31 m) ≈ 1.3 m

The second hand completes 1 revolution each minute, so in 40 min it would fully trace the circumference of a circle with radius 0.34 m a total of 40 times, so it covers a distance of

40 × 2<em>π</em> (0.34 m) ≈ 85 m

6 0
3 years ago
Light of wavelength 648.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 57.5 cm from the slit.
boyakko [2]

Answer:

71.0 \mu m

Explanation:

The formula for the single-slit diffraction is

y=\frac{n\lambda D}{d}

where

y is the distance of the n-minimum from the centre of the diffraction pattern

D is the distance of the screen from the slit

d is the width of the slit

\lambda is the wavelength of the light

In this problem,

\lambda=648.0 nm=6.48\cdot 10^{-7}m

D=57.5 cm=0.575 m

y=1.05 cm=0.0105 m, with n=2 (this is the distance of the 2nd-order minimum from the central maximum)

Solving the formula for d, we find:

d=\frac{n\lambda D}{y}=\frac{2(6.48\cdot 10^{-7} m)(0.575 m)}{0.0105 m}=7.10\cdot 10^{-5} m= 71.0 \mu m

6 0
3 years ago
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