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Elena L [17]
3 years ago
9

A soccer team wins 65% of its matches, and 15% of its matches end in a draw. If the team is scheduled to play 20 matches, about

how many matches is it expected to lose?
Mathematics
2 answers:
STatiana [176]3 years ago
5 0

Answer:  There are 4 matches that are expected to lose by a soccer team.

Step-by-step explanation:

Since we have given that

Probability that a soccer team wins = 65%

Probability that a soccer team ends in a draw = 15%

Total probability we get

65\%+15\%=80\%

Probability that matches are expected to lose is given by

100\%-80\%=20\%

Since number of matches is scheduled to play = 20

Number of matches expected to lose is given by

\frac{20}{100}\times 20\\\\=\frac{400}{100}\\\\=4

Hence, there are 4 matches that are expected to lose by a soccer team.

OLEGan [10]3 years ago
4 0
If it wins 65% and draws 15%, it loses the remaining 20%. Therefore, it is expected to lose 20%*20=4 matches.
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Please help: linear algebra problem. (Linear combinations)
DochEvi [55]

Answer:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

This tells us that:

A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]

b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right].

So we want to find a way to express this as:

Ax=b where x is the scalar vector, \left[\begin{array}{ccc}c\\d\end{array}\right].

So we can write this as:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

3 0
3 years ago
What is the radius of a circle with an area of 113.04 cubic inches? Use 3.14 for pi.
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Answer:

I am deeply sorry for the late answer

but the answer is The answer is

r ≈ 6

Step-by-step explanation:

The answer is r ≈ 6


A ≈ 113.04 cubic in.  

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d ≈ 12

and

C ≈ 37.69

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6 0
3 years ago
Chase consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Chase's body
PIT_PIT [208]

Answer:

(a) The 5-hour decay factor is 0.5042.

(b) The 1-hour decay factor is 0.8720.

(c) The amount of caffeine in Chase's body 2.39 hours after consuming the drink is 149.112 mg.

Step-by-step explanation:

The amount of caffeine in Chase's body decreases exponentially.

The 10-hour decay factor for the number of mg of caffeine is 0.2542.

The 1-hour decay factor is:

1-hour\ decay\ factor=(0.2542)^{1/10}=0.8720

(a)

Compute the 5-hour decay factor as follows:

5-hour\ decay\ factor=(0.8720)^{5}\\=0.504176\\\approx0.5042

Thus, the 5-hour decay factor is 0.5042.

(b)

The 1-hour decay factor is:

1-hour\ decay\ factor=(0.2542)^{1/10}=0.8720

Thus, the 1-hour decay factor is 0.8720.

(c)

The equation to compute the amount of caffeine in Chase's body is:

A = Initial amount × (0.8720)<em>ⁿ</em>

It is provided that initially Chase had 171 mg of caffeine, 1.39 hours after consuming the drink.

Compute the amount of caffeine in Chase's body 2.39 hours after consuming the drink as follows:

A = Initial\ amount \times (0.8720)^{2.39} \\=[Initial\ amount \times (0.8720)^{1.39}] \times(0.8720)\\=171\times 0.8720\\=149.112

Thus, the amount of caffeine in Chase's body 2.39 hours after consuming the drink is 149.112 mg.

4 0
3 years ago
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