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LenKa [72]
3 years ago
5

What is the square root of 432

Mathematics
1 answer:
Fynjy0 [20]3 years ago
6 0

√432=12√3

HOPE THIS HELPS!!!!!!!!!!!!

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If f (x) = x-2 and g (x,y) = y2 + x, then g (3, f(4)) is?
alex41 [277]
f(4)=4-2=2\\\\
g(3,f(4))=g(3,2)=2^2+3=4+3=7
4 0
3 years ago
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I really don’t understand and I need the answers to pass
cricket20 [7]

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H(10) Would be the time, in minutes the balloon spent in air . H(10) Means the balloon spent 10 minutes in air

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3 years ago
The movement of the progress bar may be uneven because questions can be worth more or less (including zera
kakasveta [241]

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600

Step-by-step explanation:

Because the tens digit is less than 5, round down to 600

5 0
2 years ago
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For each of the following vector fields F, decide whether it is conservative or not by computing curl F. Type in a potential fun
Burka [1]

Answer:

1,2 and 4 are conservatives

3 is not conservative

Step-by-step explanation:

We calculate  the Curl F

Remember that:

        Curl F = <\frac{dFz}{dy} - \frac{dFy}{dz}, \frac{dFz}{dx} - \frac{dFx}{dz}, \frac{dFy}{dx} - \frac{dFx}{dy}>

1. Curl F = <0,0,5-5> = <0,0,0>

  The potential function f so that  ∇f=F

  f(x,y,z) = -3x^{2} +5xy + 5y^{2}

  Then F is conservative

2. Curl F = < 0, 0 ,0>

  The potential function f so that  ∇f=F

  f(x,y,z) = -3/2x^{2} -y^{2}+z

  Then F is conservative

3. Curl F = <0 ,0, 10+3xsin(y) - (-cos(y))>

              = <0 ,0 , 10 +3xsin(y) + cos(y)<

 How the field's divergence is not zero the vector field is not conservative

4. Curl F = <0, 0, 0>  

  The potential function f so that  ∇f=F

  f(x,y,z) = x^{3}+(5/3)y^{3}+(5/3)z^{3}    

   Then F is conservative

5 0
3 years ago
5^(2x-1)+5^(x+1)=250<br> how do you solve?<br> thank you
zepelin [54]

Answer:

<em>x = 2</em>

Step-by-step explanation:

<u>Exponential Equations</u>

Solve:

5^{2x-1}+5^{x+1}=250

Separate each exponential:

5^{2x}5^{-1}+5^{x}5^{1}=250

Operating:

\displaystyle \frac{5^{2x}}{5}+5^{x}5=250

Multiplying by 5:

5^{2x}+25\cdot5^x=1250

Rearranging:

5^{2x}+25\cdot5^x-1250=0

Recall that:

5^{2x}=(5^{x})^2

(5^{x})^2+25\cdot5^x-1250=0

Calling

y=5^{x}:

y^2+25y-1250=0

Factoring:

(y-25)(y+50)=0

There are two possible solutions:

y=25

y=-50

Since

y=5^{x}

y cannot be negative, thus:

5^{x}=25=5^2

The solution is:

x = 2

8 0
3 years ago
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