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Ilya [14]
3 years ago
8

Marianne wanted to know students' opinion on the new schedule at school. She survey's the first

Mathematics
1 answer:
Sonja [21]3 years ago
6 0

I think it is a Convience Sampling.

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Solve 2x + 5 = 12 please help ​
kherson [118]

Answer:

first method

subtract 5 from both side

2x + 5 -5 = 12 - 5

:. 2x = 7

:. X= 2

7

divide 2 from both side

X= 2x 7

2 2

:. X= 3.5

second method

2x = 12 - 5

2x = 7

X= 2 ÷ 7

:. X= 3.5

3 0
2 years ago
Need help plzzzz will medal and fan
andriy [413]
The answer is f(x)=x²+2x when evaluated with -3 gives you the value of 3

Let's check all functions.
1. The function f(x)=x²<span>+2x when evaluated with 3 gives you the value of 3:
  Evaluated with x means that</span> x = 3.
   f(3) = 3² + 2 * 3 = 9 + 6 = 15 
   15 ≠ 3, so, this is not correct.

2. f(x)=x²<span>-3x when evaulated with -3 give you the value of 3
    Evaluated with -3 means that x = -3.
    (f-3) = (-3)</span>² - 3 * (-3) = 9 + 9 = 18 
    18 ≠ 3, so, this is not correct.

3. f(x)=x²<span>+2x when evaluated with -3 gives you the value of 3
</span>    Evaluated with -3 means that x = -3.
    f(-3) = (-3)² + 2 * (-3) = 9 - 6 = 3
    3 = 3, so this is correct.

4. f(x)=x²-3x when evaluated with -3 gives you the value of 3
    Evaluated with 3 means that x = 3.
    f(3) = (3)² - 3 * 3 = 9 - 9 = 0
    0 ≠ 3, so this is not correct.
6 0
3 years ago
Read 2 more answers
The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i
Anit [1.1K]

Answer:

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The n^{th} term of geometric sequence is given by:

a_n = ar^{n-1}

a_4 = 16 = ar^3\\a_6 = 4 = ar^5

Dividing the two equations, we get,

\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}

the first term can be calculated as:

16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128

Thus, the required geometric sequence is

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

4 0
3 years ago
Solve: 6x-9 = 3x<br> A x = 3<br> B x=1<br> C x = -1<br> D X=-3
Bumek [7]

Answer:

Answer is A, A=3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Question 1 (1 point)
salantis [7]
Blank 1: 1

Blank 2: 3

Blank 3: -2
3 0
3 years ago
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