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OLEGan [10]
3 years ago
14

I need to find the volume of a nose cone.

Mathematics
1 answer:
rjkz [21]3 years ago
8 0

well then, the volume of the nose cone will just be the sum of the volume of the cylinder below and the cone above.

since the diameter for both is 8, then their radius is half that, or 4.

\bf \stackrel{\textit{volume of a cone}}{V=\cfrac{\pi r^2 h}{3}}~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} r=4\\ h=6 \end{cases}\implies V=\cfrac{\pi (4)^2(6)}{3}\implies V=32\pi \\\\\\ \stackrel{\textit{volume of a cylinder}}{V=\pi r^2 h}~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} r=4\\ h=6 \end{cases}\implies V=\pi (4)^2(6)\implies V=96\pi \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{volume of the nose cone}}{32\pi +96\pi \implies 128\pi }\qquad \approx \qquad 402.12

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The coordinate of the partition c on the line segment is (1.2, -4.7)

<h3>How to determine the coordinates of the partition?</h3>

The coordinates are given as:

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m:n = 5:8

The coordinate of the partition is calculated using:

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So, we have:

(x,y) = \frac{1}{5 + 8} * (5 * -8 + 8 * 7, 5 * -9 + 8 * -2)

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Evaluate the product

(x,y) = (1.2, -4.7)

Hence, the coordinate of the partition on the line segment is (1.2, -4.7)

Read more about line segment ratios at:

brainly.com/question/12959377

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