Answer:
2Na + Cl2 ------> 2NaCl
4H2O2 --------> 4H2O + 2O2
CH4 + 2O2 -------> CO2 + 2H2O
Explanation:
<span>Two scientists wrote a paper detailing their research and conclusions and submitted it to a scientific journal. Several months later, they received the paper back from the publisher with many comments attached from several fellow scientists. It is either that they revise their study or replicate the study. Most scientists would revisit their work and the findings they had from their research. Most probable if they were successful and the comments of the publisher and the co-scientists were positive they could replicate the study to validate its accountability.<span>
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Answer:
34 g of NH₃ were produced in the reaction
Explanation:
N₂ (g) + 3H₂ (g) → 2NH₃ (g)
Moles of N₂ → 28 g / 28 g/m = 1 mol
Moles of H₂ → 25g / 2 g/m = 12.5 moles
Clearly, the limiting is the nitrogen.
1 mol of N₂ produced 2 moles of ammonia
So, If I have 1 mol, I'll produce the same amount
2 moles of NH₃ = Mol . Molar mass
2 m . 17 g/m = 34 g
Answer:
37S
Explanation:
Radioactivity is the spontaneous emission of particles and / or electromagnetic radiation by unstable atomic nuclei leading to their disintegration.
We have two main types of radioactivity: radioactive decay and artificial transmutation.
In radioactive decay ( natural radioactivity ), a naturally occurring radioactive element like Uranium-238 disintegrates or decays into more stable isotopes with the emission of particles and/or radiation.
23892U = 23490Th + 42He
Artificial transmutation is the collision of two particles where one particle captures the other used to bombard it. There is subsequent production of isotopes similar or different from the bombarded particle. Neutrons, alpha particles ( helium nucleus ), electrons, protons can be used to bombard elements.
147N + 42He = 178O + 11P
For the above question which is artificial transmutation, the reaction equation is
4018Ar + 10n = 3716S + 42He
So, the neutron capture by Argon-40 will produce a radioisotope Sulphur-37 with the emission of an alpha particle.
Answer:
55% plasma, 45% formed elements.
Explanation:
Hope this helps!
