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3 years ago

If the pressure on a 1.04 L sample of gas is doubled at constant temperature, please compute the new volume of gas: __

Chemistry

1 answer:

natulia [17]3 years ago

6 0

Answer:

0.52 L.

Explanation:

Let P be the initial pressure.

From the question given above, the following data were obtained:

Initial pressure (P1) = P

Initial volume (V1) = 1.04 L

Final pressure (P2) = double the initial pressure = 2P

Final volume (V2) =?

The new volume (V2) of the gas can be obtained by using the the Boyle's law equation as shown below:

P1V1 = P2V2

P × 1.04 = 2P × V2

1.04P = 2P × V2

Divide both side by 2P

V2 = 1.04P /2P

V2 = 0.52 L

Thus, the new volume of the gas is 0.52 L.

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3 years ago

Determine the specific heat of a material if a 35. Gram sample absorbed 96. Joules of energy as it was heated from 293 K to 313

podryga [215]

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Explanation:

The specific heat formula relates the heat energy required to perform a certain reaction with the mass of the reactants, specific heat and the change in temperature during the reaction.

Q = mcΔT

Here m is the mass, Q is the heat energy required, ΔT is the change in temperature and c is the specific heat.

So, if we have to determine the specific heat of the object, then we have to determine the ratio of heat required to mass of the object with change in time, as shown below.

$c = \frac{Q}{m\ \times\ delta\ T}$

As mass of the object m is given as 35 g and the energy is said to be absorbed so Q = 96 J.

The temperature values given should be changed from kelvin to celsius first. So, initial temperature 293 K will become 293-273.15 = 19.85°C.

Similarly, the final temperature will be 313 - 273.15 = 39.85°C.

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3 years ago

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the kilograms of solvent* Basically if we had 1.00 mole of sucrose (it's about 342 3 grams) and
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