Question

You are given a 0.25 M solution of sodium citrate. How would you make 3 mL of a 25-fold dilution?

Answer 1

Answer:

By adding 2.88 milliliter of water to the 0.12 milliliter of 0.25 M solution of sodium citrate will give 25-fold diluted solution.

Explanation:

25 fold dilution means that the concentration of solution is reduced by one by twenty fifth times of the original solution.

Fold - dilution = $\frac{V}{V'}$

V =Volume of original solution before dilution

V' = Total Volume of solution after dilution

V = x

V'= 3

$\frac{1}{25}=\frac{x}{3}$

x = $\frac{3}{25}mL$

Total Volume of solution after dilution = V + y

y = Amount of solvent added ( here is water)

V + 3 = 3 mL

$\frac{3}{25}mL+y=3mL$

$y=3 mL-\frac{3}{25}mL=2.88 ml$

Volume of water added = 2.88 mL

Volume of original solution  = 3 ml - 2.88 ml = 0.12 mL

By adding 2.88 milliliter of water to the 0.12 milliliter of 0.25 M solution of sodium citrate will give 25-fold diluted solution.