Answer:
a.1080km
b.63.4° S of E
c.480km/h
d.63.4° S of E
e.644km/h
Explanation:
a. Using Pythagorean theorem:
The planes magnitude is therefore 1080km
b. Given the plane's directions as 483km east and 966 west, the angle of displacement can be obtained using Trigonometric properties as:
The plane's displacement is therefore given as 63.4° S of E
c. From a, above we know the plane's magnitude as 1080km.
#We also know the time taken as 1.5h. By definition average velocity is distance over time:
#D-displacement, t=0.75+1.5=2.25h
Hence, the average velocity of the plane is 480km/h
d. Given the plane's directions as 483km east and 966 west, the angle of displacement can be obtained using Trigonometric properties as:
The plane's displacement is therefore given as 63.4° S of E
e. Average speed is the total distance divided by total time taken.
Total time =45min+1.5h=2.25
Total distance=483+966=1449km
Therefore the speed is calculated as:
The average speed of the plane is 644km/h