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Ray Of Light [21]
3 years ago
10

A satellite system that has unique properties is the ____ satellite, which is used by governments for spying and by scientific a

gencies for observing celestial bodies
Physics
2 answers:
agasfer [191]3 years ago
6 0

Answer: Highly-elliptical-earth-orbit (heo)

Explanation: Highly-elliptical-earth-orbit (heo) satellite system has unique properties

which is used by governments for spying and by scientific agencies for observing celestial bodies. It is an extremely elongated orbit that is useful for communication satellites which creates signals between a source transmitter and a receiver at different locations on earth. They are used by government for spying, scientific agencies for observing celestial bodies, for the internet and telephone communications.

NARA [144]3 years ago
3 0

Answer:

Highly elliptical satellite orbit.

Explanation:

Highly elliptical satellite orbit is used to provide coverage over any point on the globe. The HEO is not limited to equatorial orbits like the geostationary orbit and the resulting lack of high latitude and polar coverage.

As a result of its ability to provide high latitude and polar coverage, countries such as Russia which need coverage over polar and near polar areas make significant use of highly elliptical orbits, HEO. With two satellites in any orbit, they are able to provide continuous coverage.

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If there are 20 Earthworms in a garden that covers 5 square meters, what is the population density of the earthworms?
hodyreva [135]

I think, I do think.. that it is D.

Wouldn't it be simple to divide 5 from 20, that would equal 4.

4 earthworms per square meter.

3 0
3 years ago
Read 2 more answers
2. For each pair of variables, identify which is the independent and which is the dependent variable. a. How much gas is left in
Korvikt [17]

For each pair Independent variable and the dependent variable is -

a. How much gas is left in the gas tank vs. how far the car has traveled.

  • Independent variable =  how far the car has traveled
  • dependent variable = How much gas is left in the gas tank

b. How much money you've spent vs. how much money is in your wallet.

  • Independent variable =  How much money you've spent
  • dependent variable = how much money is in your wallet.

c. How far a toy car traveled vs. how much time went by​

  • Independent variable =  how much time went by​
  • dependent variable = How far a toy car traveled

An independent variable in any experiment or research is a variable that is manipulated or changed in the experiment, this change leads to a direct effect on the dependent variable.

A dependent variable is a variable that is directly affected by the independent variable and it is the variable that is measured or tested in an experiment.

Thus,

a. How much gas is left in the gas tank vs. how far the car has traveled.

  • Independent variable =  how far the car has traveled
  • dependent variable = How much gas is left in the gas tank

b. How much money you've spent vs. how much money is in your wallet.

  • Independent variable =  How much money you've spent
  • dependent variable = how much money is in your wallet.

c. How far a toy car traveled vs. how much time went by​

  • Independent variable =  how much time went by​
  • dependent variable = How far a toy car traveled

Learn more about dependent variables:

brainly.com/question/1670595:

3 0
2 years ago
A star is moving away from an observer at 1% of the speed of light. At what wavelength would the observer find an emission line
Ivan

Answer:

  λ = 5940 Angstroms

Explanation:

This is an exercise of the relativistic Doppler effect

        f’= f  √((1- v / c) / (1 + v / c))

Where the speed in between the strr and the observer is positive if they move away

Let's use the relationship

         c = λ f

         f = c /λ

We replace

              c /λ’ = c /λ  √ ((1- v / c) / (1 + v / c))

              λ = λ’ √ ((1- v / c) / (1 + v / c))

Let's calculate

             v = 0.01 c

             v = 0.01 3 10⁸

             v=  3 10⁶ m / s

             λ = 6000 √ [(1- 3 10⁶/3 10⁸) / (1+ 3 10⁶/3 10⁸)]

             λ = 6000 √ [0.99 / 1.01]

             λ = 5940 Angstroms

6 0
3 years ago
A mass free to vibrate on a level, frictionless surface at the end of a horizontal spring is pulled 35 cm from its equilibrium p
saul85 [17]

Answer:

0.67 s

Explanation:

This is a simple harmonic motion (SHM).

The displacement, x, of an SHM is given by

x = A\cos(\omega t)

A is the amplitude and \omega is the angular frequency.

We could use a sine function, in which case we will include a phase angle, to indicate that the oscillation began from a non-equilibrium point. We are using the cosine function for this particular case because the oscillation began from an extreme end, which is one-quarter of a single oscillation, when measured from the equilibrium point. One-quarter of an oscillation corresponds to a phase angle of 90° or \frac{\pi}{4} radian.

From trigonometry, \sin A =\cos B if A and B are complementary.

At t = 0, x = 3.5

3.5 = A\cos(\omega \times0)

A =3.5

So

x = 3.5\cos(\omega t)

At t = 0.12, x = 1.5

1.5 = 3.5\cos(0.12\omega)

\cos(0.12\omega)=\dfrac{1.5}{3.5}=0.4286

0.12\omega =\cos^{-1}0.4286

0.12\omega = 1.13

\omega = 9.4

The period, T, is related to \omega by

T = \dfrac{2\pi}{\omega} = \dfrac{2\times3.14}{9.4}=0.67

5 0
3 years ago
A 10.0 kg weather rocket generates a thrust of 230 NN . The rocket, pointing upward, is clamped to the top of a vertical spring.
blondinia [14]

Answer: 0.2m

Explanation: Firstly only the Rocket's Weight Compress the spring which can be found by

F_r=M_r*g\\F_r=10*9.81\\F_r=98.1N

According to Hooks Law

F_r=k*x\\x=F_r/k\\x=98.1/480\\x=0.2m

The part b and c of this question is done in the attachment

7 0
3 years ago
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