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3 years ago

What generates the magnetic field that surrounds a wire carrying an electric current?

Physics

1 answer:

Luba_88 [7]3 years ago

8 0

Answer:

Electric current produces a magnetic field. This magnetic field can be visualized as a pattern of circular field lines surrounding a wire. ... Magnetic Field Generated by Current: (a) Compasses placed near a long straight current-carrying wire indicate that field lines form circular loops centered on the wire.

Explanation:

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The wavelength of the yellow light from a sodium flame is 589 nm. This light originated from a sodium atom in the hot flame.

DiKsa [7]

From wave speed formula, period is 1.96 × 10^-15 seconds per cycle and the frequency is 5.1 × 10^14 Hertz

<h3>What is Frequency ?</h3>

The frequency of a wave is the number of complete revolution per second made by a vibrating body.

Given that the wavelength of the yellow light from a sodium flame is 589 nm. This light originated from a sodium atom in the hot flame.

(a) In the sodium atom from which this light originated, the period of the simple harmonic motion which was the source of this electromagnetic wave will be found by using the formula

v = λ/T

Where

v = speed of light = 300,000,000 m/s

λ = wavelength = 589 × 10^-9 m

T = period

Substitute all the parameters

300000000 = 589 × 10^-9/T

T = 589 × 10^-9/300000000

T = 1.96 × 10^-15 seconds per cycle.

(b) The frequency of this light wave is the reciprocal of its period. That is,

F = 1/T

F = 1/1.96 × 10^-15

F = 5.1 × 10^14 Hertz

Therefore, the period of the wave is 1.96 × 10^-15 seconds per cycle and its frequency is 5.1 × 10^14 Hertz

Learn more about Light Wave here: brainly.com/question/10728818

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6 0

2 years ago

A feather is dropped on the moon from the height of 1.4m. The acceleration of gravity on the moon is 1.67ms-1. Determine the tim

Zinaida [17]

1.3s

Explanation:

Given parameters:

Height = 1.4m

Gravity on moon = 1.67ms⁻¹

Unknown:

Time for feather to fall = ?

Solution:

To solve this problem, we are going to use one of the motion equation that relates time, gravity and height.

H = ut + $\frac{1}{2} g t^{2}$

Sine the body was dropped from rest, initial velocity is zero;

H = height

u = initial velocity

t = time

g = acceleration due to gravity

since u = 0;

H = $\frac{1}{2} g t^{2}$

1.4 = $\frac{1}{2}$ x 1.67 x t²

t = 1.3s

learn more:

Gravity brainly.com/question/10934170

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8 0

3 years ago

If a certain mass of mercury has a volume of 0.002 m^3 at a temperature of 20°c, what will be the volume at 50°c

V125BC [204]

Change in volume = mass x coefficient of linear expansion x change in temperature
.002 x .0001802 x 30 = .000010812

initial volume + change in volume = Final volume
.002 + .000010812 = .002010812 m cubed

5 0

3 years ago

Read 2 more answers

A ball is launched at an angle of 10 degrees from a 20 meter tall building with a speed of 4 m/s. How long is the ball in the ai

shutvik [7]

Answer:

d) None of the above

Explanation:

$v_{o}$ = inituial velocity of launch = 4 m/s

θ = angle of launch = 10 deg

Consider the motion along the vertical direction

$v_{oy}$ = initial velocity along vertical direction = 4 Sin10 = 0.695

m/s

$a_{y}$ = acceleration along the vertical direction = - 9.8 m/s²

y = vertical displacement = - 20 m

t = time of travel

using the equation

$y=v_{oy} t+(0.5)a_{y} t^{2}$

- 20 = (0.695) t + (0.5) (- 9.8) t²

t = 2.1 sec

consider the motion along the horizontal direction

x = horizontal displacement

$v_{ox}$ = initial velocity along horizontal direction = 4 Cos10 = 3.94 m/s

$a_{x}$ = acceleration along the horizontal direction = 0 m/s²

t = time of travel = 2.1 s

Using the kinematics equation

$x =v_{ox} t+(0.5)a_{x} t^{2}$

x = (3.94) (2.1) + (0.5) (0) (2.1)²

x = 8.3 m

Consider the motion along the vertical direction

$v_{oy}$ = initial velocity along vertical direction = 4 Sin10 = 0.695

m/s

$a_{y}$ = acceleration along the vertical direction = - 9.8 m/s²

$y_{o}$ =initial vertical position at the time of launch = 20 m

$y$ = vertical position at the maximum height = 20 m

$v_{fy}$ = final velocity along vertical direction at highest point = 0 m/s

using the equation

${v_{fy}}^{2}= {v_{oy}}^{2} + 2 a_{y}(y - y_{o})$

$0^{2}= 0.695^{2} + 2 (- 9.8)(y - 20)$

$y$ = 20.02 m

h = height above the starting height

h = $y$ - $y_{o}$

h = 20.02 - 20

h = 0.02 m

7 0

4 years ago

If a cannonball is fired horizontally it will not go in a straight line why?

goldfiish [28.3K]

Explanation:

A projectile (Cannon ball) is launched at an angle to the horizontal and rises up to a peak while moving horizontally. When it reaches the peak, the projectile starts to fall.

5 0

2 years ago