Answer:
The water shoots 15.31 m high above the street level.
Explanation:
The gauge pressure drives the motion of the water to whixhever height it will attain. The expression relating the gauge pressure to the height reached by the water, is
P = ρgh
P = Gauge Pressure = 150 kPa = 150,000 Pa
ρ = density of the fluid (water) = 1000 kg/m³
g = acceleration due to gravity = 9.8 m/s²
h = Height reached by the water = ?
150,000 = 1000 × 9.8 × h
h = (150000) ÷ 9800 = 15.306 = 15.31 m
Hope this Helps!!!
Answer:
True - Archimedes Principle states that the buoyant force on an object is equal to the weight of the liquid displaced.
The distance d₁ it rises from rest while the engine is burning is given by
d₁ = d₀ + v₀t + (1/2)at²
d₁ = 0 + 0 + (1/2)·(29.4 m/s²)·(3.98 s)² = 232.85 m
So it gets to 232.85 m and then runs out of fuel. Its velocity v₁ at this point is given by
v₁ = v₀ + at = (29.4 m/s²)·(3.98 s) = 117 m/s
At this point, gravity begins to slow it down until it reaches its peak where its velocity v₂ is zero.
v₂² = v₁² + 2ad₂
where d₂ is the distance it rises until v=0
Since gravity is decelerating the rocket, a = -g, and we have
0² = (117 m/s)² + 2(-9.8 m/s²)d₂
0 = (117)² - (19.6)·d₂
0 = 13,689 - (19.6)·d₂
d₂ = 13,689/19.6 = 698.42 m
So the total height it rises is given by
d₁ + d₂ = 232.85 m + 698.42 m
= 931.27 m
The answer is: [D]: "have rings and bands" .
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