Phosgene on reacting with <span>phenylmagnesium bromide generates
benzoyl chloride.
Since, </span>phenylmagnesium bromide is added in excess. It would further react with benzoyl chloride to form
benzophenone.
Benzophenone on further reacting with phenylmagnesium bromide, and aqueous treatment, gives
triphenylmethanol.
Entire reaction pathways is shown below:
Rubidium or strontium have larger a larger atomic radius since the further left on the periodic table you go, the larger the sizes of the atoms are. This trend can be explained through effective nuclear charge which explains how the further left and down you go, the less the atoms nucleus is able to pull in the electrons around it.<span />
Explanation:
2.04 % hydrogen
32.65% sulphur
65.31% is oxygen
atomic ratio
hydrogen =2.04÷1=2.04
sulphur =32.65÷32=1.02
oxygen =65.31÷16=4.08
simplest ratio
hydrogen = 2.04÷1.02=2
sulphur =1.02÷1.02=1
oxygen =4.08÷1.02=4
empirical formula is H2SO4
Answer: limiting reactant (or limiting reagent): The reactant that determines the amount of product that can be formed in a chemical reaction.
Explanation: Your welcome buddy.
It seems like I begin to forget whole organic Chemistry. Anyway, the answer is 2-methylheptane-3-yne.
To build a name for this molecule, you need to:
1. Determine where there is the lowest chain beginning with the double, triple bond, or there is other thing for other types of organic molecules.. In this case you have one triplet bond, and the lowest chain there is the one that is below the bond.
2. In this small chain you see one "forks": CH3 and another CH3 go from the one CH. Put number 1 where there are the most number of such compounds, in this case it doesn't matter because we have one CH3 in one way and one CH3 in the another.
3. Determine the largest chain which surely has the triple bond. Put the numbers from 2 to the final beginning with CH3 where you put number 1. Your largest chain consists of 7 particles CH3, CH2, and CH.
4. You see that you also have one unnamed particle, the one which is "the other way" when you are in the CH which is below the triple bond on the picture. Its name will be 2-methyl because it is connected with particle #2 and it consists only of one carbon. If there were 2, it would be ethyl, and so on.
5. Finally, let's write a full name: put 2-methyl first, "2-methyl." Then, write a full name for the chain of 7 carbons, which has to be heptane, if it had 5, you would name it pentane, ethane, and so on. So, we have "2-methylheptane." Finally, you see that you have a triple bond after the carbon #3. Put a dash and the number of this carbon. "2-methylheptane-3" you should have. Since it is alkyne (organic molecule with one triple bond), you have to write "yne" at the end.
the final name is "2-methylheptane-3-yne." You can answer the question "explain your naming process" by using the answer I provided. Hope it helps. Good luck!
