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Vedmedyk [2.9K]
3 years ago
8

Bonds. Carbon dioxide has a. Ionic b. Covalent c. Nonpolar covalent d. Polar covalent​

Chemistry
1 answer:
Luden [163]3 years ago
7 0

Answer:

B

Explanation:

Covalent bond.

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D. a new technology.
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10. Which statement about cellular respiration in plants and animals is true?
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Ⓑ Both plants and animals release energy from glucose/sugar in cellular respiration.

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How many moles of carbon in 6.64 moles of CCl2 F
Bad White [126]

Answer: 6.64 moles of carbon.

Explanation:

Given data:

Number  of moles of C = ?

Number of moles of CCl₂F₂ = 6.64 mol

Solution:

In one mole of CCl₂F₂ there is one mole of carbon two moles of chlorine and two moles of fluorine are present.

In 6.6 moles of CCl₂F₂ :

Moles of carbon = 6.64 × 1 = 6.64 moles of carbon.

Moles of chlorine = 6.64× 2 = 13.28 moles of chlorine

Moles of fluorine = 6.64× 2 = 13.28 moles of fluorine

Read more on Brainly.com - brainly.com/question/15602143#readmore

3 0
3 years ago
A sample of propane(c3h8)has 3.84x10^24 H atoms.
deff fn [24]

Answer:

A) 14. 25 × 10²³ Carbon atoms

B) 34.72 grams

Explanation:

1 molecule of Propane has 3 atoms of Carbon and 8 atoms of Hydrogen.

The sample has 3.84 × 10²⁴ H atoms.

If 8 atoms of Hydrogrn are present in 1 molecule of propane.

3.84 × 10²⁴ H atoms are present in

\mathfrak{ \frac{3.8 }{8} \times 10 ^{24}}

<u>= 4.75 × 10²³ molecules of Propane</u>.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

No. of Carbon atoms in 1 molecule of propane = 3

=> C atoms in 4.75× 10²³ molecules of Propane = 3 × 4.75 × 10²³

<u>= 14.25 × 10²³ </u>

<u>________________________________________</u>

<u>Gram</u><u> </u><u>Molecular</u><u> </u><u>Mass</u><u> </u><u>of</u><u> </u><u>Propane</u><u>(</u><u>C3H8</u><u>)</u>

= 3 × 12 + 8 × 1

= 36 + 8

= 44 g

1 mole of propane weighs 44g and has 6.02× 10²³ molecules of Propane.

=> 6.02 × 10²³ molecules of Propane weigh = 44 g

=> 4. 75 × 10²³ molecules of Propane weigh =

\mathsf{ \frac{44 }{6.02 \times  {10}^{23} } \times 4.75 \times  {10}^{23}  }

\mathsf{  = \frac{44 }{6.02 \times   \cancel{{10}^{23} }} \times 4.75 \times \cancel{ {10}^{23}}  }

\mathsf{  = \frac{44 }{6.02 } \times 4.75   }

<u>= 34.72 g</u>

8 0
2 years ago
Can you help me on my little brother question What are the three forms of matter?
Eva8 [605]
No doubt it's B. solid, liquid, and gas.

Hope this helps!
7 0
2 years ago
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