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ASHA 777 [7]
3 years ago
12

Complete and balance the precipitation reactions. Include physical states. Refer to the solubility rules as necessary. precipita

tion reaction: Ba(NO3)2(aq)+CuSO4(aq)⟶BaSO4+CU(NO3)2 Ba ( NO 3 ) 2 ( aq ) + CuSO 4 ( aq ) ⟶ BaSO 4 + CU ( NO 3 ) 2 precipitation reaction: K3PO4(aq)+MgCl2(aq)⟶6KCl(aq)+Mg3(PO4)2(s) K 3 PO 4 ( aq ) + MgCl 2 ( aq ) ⟶ 6 KCl ( aq ) + Mg 3 ( PO 4 ) 2 ( s )
Chemistry
1 answer:
Darya [45]3 years ago
4 0
<h3>Answer:</h3>

Ba(NO₃)₂(aq) + CuSO₄(aq) ⟶ BaSO₄(s) + CU(NO₃)₂(aq)

2K₃PO₄(aq) + 3MgCl₂(aq) ⟶ 6KCl(aq) + Mg₃(PO₄)₂(s)

<h3>Explanation:</h3>
  • Precipitation reactions are types of reactions that involve a reaction between soluble salts to form an insoluble salt or a precipitate and a soluble salt.
  • The equations given in the question are examples of precipitation reactions that lead to the formation of precipitates BaSO₄ and Mg₃(PO₄)₂
  • The balanced equations are;

Ba(NO₃)₂(aq) + CuSO₄(aq) ⟶ BaSO₄(s) + CU(NO₃)₂(aq)

2K₃PO₄(aq) + 3MgCl₂(aq) ⟶ 6KCl(aq) + Mg₃(PO₄)₂(s)

  • Based on solubility rules, all sulfates are soluble except CaSO₄, BaSO₄, PbSO₄ and silver sulfate. Therefore, BaSO₄ is a precipitate and will have a solid-state.
  • All phosphates are insoluble except those of ammonium, potassium, and sodium. Therefore, Mg₃(PO₄)₂ is a precipitate and will have a soluble state.

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7 0
2 years ago
2. Al + Fe2O3 → Al2O3 + Fe (Need to balance equation)
shtirl [24]
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All atoms of a given element are identical was proven wrong because of the existence or
vagabundo [1.1K]

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Explanation:

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3 years ago
Use Boyle’s law to complete the following:
mixas84 [53]

Answer:

The answer to your question is: 0.25 l

Explanation:

Data

P1 = 1 atm

V1 = 0.5 l

P2 =2 atm

V2 = ?

T = constant

Formula

          V1P1 = V2P2

Clear V2 from the formula

            V2 = V1P1/P2

Substitution

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3 0
3 years ago
What is the percent of Cr in Cr2O3
IgorLugansk [536]
The percentage of Chromium in Chromium Oxide is calculated as follow,

Step 1:
           Calculate Molar mass of Cr₂O₃,
Cr = 51.99 u
O = 16 u
So,
     2(51.99) + 3(16) = 103.98 + 48 = 151.98 u

Step 2:
          Secondly divide molar mass of only chromium with total mass of Cr₂O₃ and multiply with 100.
i.e.
                   = \frac{103.98}{151.98} × 100
                   
                   = 68.41 %
So, the %age composition of chromium in chromium oxide is 68.41 %.
5 0
3 years ago
Read 2 more answers
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