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Yuliya22 [10]
3 years ago
9

What mass of sucrose (C12H22O11) should be combined with 546 g of water to make a solution with an osmotic pressure of 8.80 atm

at 290 K ? (Assume the density of the solution to be equal to the density of the solvent.)
Chemistry
1 answer:
lesya [120]3 years ago
5 0

<u>Answer:</u> The mass of sucrose required is 69.08 g

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = 8.80 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (sucrose) = ?

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 564 mL    (Density of water = 1 g/mL)

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

T = Temperature of the solution = 290 K

Putting values in above equation, we get:

8.80atm=1\times \frac{\text{Mass of sucrose}\times 1000}{342.3\times 546}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 290K\\\\\text{Mass of sucrose}=\frac{8.80\times 342.3\times 546}{1\times 1000\times 0.0821\times 290}=69.08g

Hence, the mass of sucrose required is 69.08 g

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The question is incomplete, complete question is;

A solution of Na_2CO_3 is added dropwise to a solution that contains1.15\times 10^{-2} M of Fe^{2+} and 0.58\times 10^{-2} M and Cd^{2+}.

What concentration of CO_3^{2-} is need to initiate precipitation? Neglect any volume changes during the addition.

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K_{sp} value CdCO_3: 1.80\times 10^{-14}

What concentration of CO_3^{2-} is need to initiate precipitation of the first ion.

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The expression of an solubility product of iron(II) carbonate :

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2) CdCO_3\rightleftharpoons Cd^{2+}+CO_3^{2-}

The expression of an solubility product of cadmium(II) carbonate :

K_{sp}=[Cd^{2+}][CO_3^{2-}]

1.80\times 10^{-14}=0.58\times 10^{-2} M\times [CO_3^{2-}]

[CO_3^{2-}]=\frac{1.80\times 10^{-14}}{0.58\times 10^{-2} M}

[CO_3^{2-}]=3.103\times 10^{-12} M

On comparing the concentrations of carbonate ions for both metallic ions, we can see that concentration to precipitate out the cadmium (II) carbonate from the solution is less than concentration to precipitate out the iron (II) carbonate from the solution.

So, cadmium carbonate will precipitate out first.

And the concentration of carbonate ions to start the precipitation of cadmium carbonate we will need concentration of carbonate ions greater than the 3.103\times 10^{-12} M concentration.

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