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grigory [225]
3 years ago
15

How Many Atoms Are In 356.13 Grams Of Sn

Chemistry
1 answer:
s344n2d4d5 [400]3 years ago
8 0

<span>There are three atoms of Sn (Stannous or Tin) in</span> 356.13 g of Sn.

<span>One atom of Sn has the atomic mass (m</span>ₐ<span>) of </span>118,71u which means:

356.13/118.71=3 atoms of Sn

The mass number (symbol A) also called atomic mass number or nucleon number is the total number of protons and neutrons in an atomic nucleus. It determines the atomic mass of atoms and it is in the periodic table.

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M1 = 3M M2 = 1.25M V1 = V1=.125L unkown What is V2?
mylen [45]

0.3 L is the final volume when M₁ = 3 M, V₁ = 0.125L, M₂ = 1.25M.

<h3>What is volume?</h3>

The amount of space occupied by a three-dimensional figure as measured in cubic units.

Given data:

M₁ = 3 M

V₁ = 0.125L

M₂ = 1.25M

V₂ = ?

Solution:

M₁V₁ = M₂V₂

3 M × 0.125L = 1.25M × V₂

V₂ = 0.3 L

Hence, 0.3 L is the final volume.

Learn more about volume here:

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2 years ago
The metric system is also known as the
slega [8]

Answer:

THE answer is all of above

Explanation:

3 0
3 years ago
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What's 2x2 please help ​
podryga [215]

Answer:

2 x 2 = 4

Explanation:

Multiplication is just doubling the numbers depending on what you have. 3 x 3 = 9 because 3 three times is 9. Therefore, 2 two times is 4.

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3 years ago
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50.g of NaNO3 was dissolved in 1250 mL of water. what is the molality of the solution? [ Molar mass of NaNO3 = 85 g/mol
Viefleur [7K]

Answer:

Approximately 0.47\; \rm mol \cdot L^{-1} (note that 1\; \rm M = 1 \; \rm mol \cdot L^{-1}.)

Explanation:

The molarity of a solution gives the number of moles of solute in each unit volume of the solution. In this \rm NaNO_3 solution in water,

Let n be the number of moles of the solute in the whole solution. Let V represent the volume of that solution. The formula for the molarity c of that solution is:

\displaystyle c = \frac{n}{V}.

In this question, the volume of the solution is known to be 1250\; \rm mL. That's 1.250\; \rm L in standard units. What needs to be found is n, the number of moles of \rm NaNO_3 in that solution.

The molar mass (formula mass) of a compound gives the mass of each mole of units of this compound. For example, the molar mass of \rm NaNO_3 is 85\; \rm g \cdot mol^{-1} means that the mass of one mole of

\displaystyle n = \frac{m}{M}.

For this question,

\begin{aligned}&n\left(\mathrm{NaNO_3}\right) \\ &= \frac{m\left(\mathrm{NaNO_3}\right)}{M\left(\mathrm{NaNO_3}\right)}\\&= \frac{50\; \rm g}{85\; \rm g \cdot mol^{-1}} \\& \approx 0.588235\; \rm mol\end{aligned}.

Calculate the molarity of this solution:

\begin{aligned}c &= \frac{n}{V} \\&= \frac{0.588235\; \rm mol}{1.250\; \rm L} \\&\approx 0.47\;\rm mol \cdot L^{-1}\end{aligned}.

Note that 1\; \rm mol \cdot L^{-1} (one mole per liter solution) is the same as 1\; \rm M.

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There will be a shift towards the reactants
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