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3 years ago

5

4. A total of 226 J of heat are absorbed as 58.3 g of lead is heated from 12.0oC to 42.0oC. From this data, what is the specific

heat of lead?

1 answer:

Zanzabum3 years ago

6 0

C = Q / M * ΔT

Δf - Δi = 42.0ºC - 12.0ºC = 30.0ºC

C = 226 J / 58.3 * 30.0

C = 226 / 1749

C = 0.129 J/gºC

hope this helps!

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Read 2 more answers

Baking soda (NaHCO3) and vinegar (HC2H3O2) react to form sodium acetate, water, and carbon dioxide. If 42.00 g of baking soda re

Setler [38]

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Mole = mass / molar mass

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Next, balanced equation for the reaction. This is given below:

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From the balanced equation above,

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Finally, we shall determine the number of mole of CO₂ produced by the reaction of 42 g (i.e 0.5 mole) of NaHCO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.

Therefore, 0.5 mole of NaHCO₃ will also react to produce 0.5 mole of CO₂.

Thus, 0.5 mole of CO₂ was obtained from the reaction.

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