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grigory [225]
3 years ago
5

4. A total of 226 J of heat are absorbed as 58.3 g of lead is heated from 12.0oC to 42.0oC. From this data, what is the specific

heat of lead?
Chemistry
1 answer:
Zanzabum3 years ago
6 0
C = Q / M * ΔT

Δf - Δi = 42.0ºC - 12.0ºC = 30.0ºC

C =  226 J / 58.3 * 30.0

C = 226 / 1749

C = 0.129 J/gºC

hope this helps!

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gladu [14]

Na⁺,SO₄²⁻ is the answer

<h3>Further explanation </h3>

An ion is an atom or molecule that has a net electrical charge. There are many ions, one of them are sodium ion and sulfate ion.

SO₄²⁻ or Sulfate is a naturally occurring polyatomic ion that consist of a central sulfur atom surrounded by four oxygen atoms with occured widely in everyday life. Sodium ions are important for regulation of blood and body fluids, transmission of nerve impulses, heart activity, and certain metabolic functions.

Whereas Na⁺ or Sodium is a chemical element with the symbol Na and atomic number 11. It is a soft, silvery-white, highly reactive metal. Sulfate ion is a very weak base. Therefore sulfate ion undergoes negligible hydrolysis in aqueous solution.

Enter the symbol of a sodium ion, Na⁺, followed by the formula of a sulfate ion, SO₄²⁻. Separate the ions with a comma only—spaces are not allowed. Express your answers as ions separated by a comma. Therefore the answer is: Na⁺,SO₄²⁻

Hope it helps!

<h3>Learn more</h3>
  1. Learn more about sodium ion brainly.com/question/6839866
  2. Learn more about sulfate ion brainly.com/question/2763823
  3. Learn more about ions brainly.com/question/11852357

<h3>Answer details</h3>

Grade:  9

Subject:  Chemistry

Chapter:  Introduction to Mastering Chemistry

Keywords: sodium ion, sulfate ion, ions, Chemistry, symbol

6 0
3 years ago
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A solution has a poh of 7. 1 at 10∘c. what is the ph of the solution given that kw=2. 93×10−15 at this temperature? remember to
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A solution has a pOH of 7. 1 at 10∘c. Then the pH of the solution given that kw=2. 93×10−15 at this temperature is 7.4 .

It is given that,

pOH of solution = 7.1

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Firstly, we will calculate the value of pKw

The expression which we used to calculate the pKw is,

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Now by putting the value of Kw in this expression,

pKw =−log{2.93×10^(-15)}

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Now we have to calculate the pH of the solution.

As we know that,

pH+pOH=pKw

Now put all the given values in this formula,

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7 0
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jok3333 [9.3K]

The valence electron does the halogens possess are 7

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Hence the halogens posses 7 valence electron

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