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barxatty [35]
2 years ago
8

Please answer this fast

Physics
2 answers:
Olegator [25]2 years ago
6 0

Answer:?

D. They cant travel through a vacuum

Natali5045456 [20]2 years ago
3 0

the answer choice will be A because they travel at the same speed through only light not one material.

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Plastics are used in millions of objects we use every day. Why are plastics NOT considered natural resources?
jeka57 [31]

Answer:

B

Explanation:

Yes plastic is artficial

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Cu2+

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Newton's second law problem. The spring constant can be determined from the balance of forces in equilibrium. Suppose the spring
mario62 [17]

Answer:

K =6.697 Kg/s²

Explanation:

Given:

delta m =41 g = 0.041 kg

delta x = 6cm = 0.06m

g = 9.8 m/s²

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K = delta m g /delta x

K = (0.041 kg × 9.8 m/s²) / 0.06m

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If a fish is trying to capture an insect hovering above the surface of the water – how will it jump to catch it? Will it aim abo
Viktor [21]

Answer:

It will have aim at a point "below" the insect.

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2 years ago
A high-jumper, having just cleared the bar, lands on an air mattress and comes to rest. Had she landed directly on the hard grou
Hoochie [10]

Answer:

e. the air mattress exerts the same impulse, but a smaller net avg force, on the high-jumper than hard-ground.

Explanation:

This is according to the Newton's second law and energy conservation that the force exerted by the hard-ground is more than the force exerted by the mattress.

The hard ground stops the moving mass by its sudden reaction in the opposite direction of impact force whereas the mattress takes a longer time to stop the motion of same mass in a longer time leading to lesser average reaction force.

<u>Mathematical expression for the Newton's second law of motion is given as:</u>

F=\frac{dp}{dt} ............................................(1)

where:

dp = change in momentum

dt = time taken to change the momentum

We know, momentum:

p=m.v

Now, equation (1) becomes:

F=\frac{d(m.v)}{dt}

<em>∵mass is constant at speeds v << c (speed of light)</em>

\therefore F=m.\frac{dv}{dt}

and, \frac{dv}{dt} =a

where: a = acceleration

\Rightarrow F=m.a

also

F\propto \frac{1}{dt}

so, more the time, lesser the force.

<em>& </em><u><em>Impulse:</em></u>

I=F.dt

I=m.a.dt

I=m.\frac{dv}{dt}.dt

I=m.dv=dp

∵Initial velocity and final velocity(=0), of a certain mass is same irrespective of the stopping method.

So, the impulse in both the cases will be same.

4 0
3 years ago
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