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FromTheMoon [43]
3 years ago
9

while working out a man performed 2525j of work in 19seconds . what was his power A:132.9w. B:241.5w C 47.975w. D100.5w

Physics
2 answers:
Olenka [21]3 years ago
7 0
A: 132.9w because 2525\19 is how much energy transferred per second which is also known as the power
tamaranim1 [39]3 years ago
6 0

Answer:

Power of the man is 132.9 W.

Explanation:

Given that,

Work performed by the man is 2525 J

Time for which the work is performed is 19 second

To find :

Power of the man

Solve :

Let P is the power of the man. The total work done divided by time taken is called the power of an object. Its formula is given by :

P=\dfrac{W}{t}

P=\dfrac{2525\ J}{19\ s}

P=132.89\ W

or

P=132.9\ W

Therefore, the power of the man is 132.9 W.

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The main purpose of an air bag is to stop a passenger during a car accident in a greater amount of time than if the air bag were
Simora [160]

Answer:

a) 45571 N  

b) 22786 N

c) 4557 N

Explanation:

  • Since the goal of the airbag is helping the person to stop after the collision in a greater time, this means that the change in momentum must finish when this is just zero.
  • In other words, the change in momentum, must be equal to the initial one, but with opposite sign.

       \Delta p = - p_{o} = -m*v = -55 kg*29m/s = -1595 kgm/s (1)

  • Now, just applying the original form of  Newton's 2nd Law, we know that this change in momentum must be equal to the impulse needed to stop the person:

       \Delta p = F* \Delta t  (2)

  • So, as we know the magnitude of Δp from (1) and we have different Δt as givens, we can get the different values of F (in magnitude) required to stop the person for each one of them, as follows:

       F_{1} = \frac{\Delta p}{\Delta t_{1}} = \frac{1595kgm/s}{0.035s} = 45571 N (3)

       F_{2} = \frac{\Delta p}{\Delta t_{2}} = \frac{1595kgm/s}{0.07s} = 22786 N (4)

       F_{3} = \frac{\Delta p}{\Delta t_{3}} = \frac{1595kgm/s}{0.35s} = 4557 N (5)

4 0
3 years ago
Rainfall occurs on the earth due to effect of gravity​
Anna [14]

<em>Answer:</em>

<h3><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>True</em></h3>

  • <em>Because </em><em>Gravity is the force of attraction between two objects, and Earth's gravity pulls matter downward, toward its center. It pulls precipitation down from clouds and pulls water downhill. Gravity also moves air and ocean water. ... Gravity pulls denser air and water downward, forcing less dense air and water to move upward.</em>

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3 0
2 years ago
A very long straight wire has charge per unit length 1.44×10-10C/m.
4vir4ik [10]

Answer:

Distance of the point where electric filed is 2.45 N/C is 1.06 m            

Explanation:

We have given charge per unit length, that is liner charge density \lambda =1.44\times 10^{-10}C/m

Electric field E = 2.45 N/C

We have to find the distance at which electric field is 2.45 N/C

We know that electric field due to linear charge is equal to

E=\frac{\lambda }{2\pi \epsilon _0r}, here \lambda is linear charge density and r is distance of the point where we have to find the electric field

So 2.45=\frac{1.44\times 10^{-10} }{2\times 3.14\times 8.85\times 10^{-12}\times r}

r = 1.06 m

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3 0
3 years ago
(a) what will an object weigh on the moon's surface if it weighs 100 n on earth's surface
juin [17]
We know the equation

weight = mass × gravity

To work out the weight on the moon, we will need its mass, and the gravitational field strength of the moon.
Remember that your weight can change, but mass stays constant.

So using the information given about the earth weight, we can find the mass by substituting 100N for weight, and we know the gravity on earth is 10Nm*2 (Use the gravitational field strength provided by your school, I am assuming yours in 10Nm*2)

Therefore,

100N = mass × 10
mass= 100N/10
mass= 10 kg

Now, all we need are the moon's gravitational field strength and to apply this to the equation

weight = 10kg × (gravity on moon)
4 0
3 years ago
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