while working out a man performed 2525j of work in 19seconds . what was his power A:132.9w. B:241.5w C 47.975w. D100.5w
2 answers:
Answer:
Power of the man is 132.9 W.
Explanation:
Given that,
Work performed by the man is 2525 J
Time for which the work is performed is 19 second
To find :
Power of the man
Solve :
Let P is the power of the man. The total work done divided by time taken is called the power of an object. Its formula is given by :
or
Therefore, the power of the man is 132.9 W.
You might be interested in
Assuming the driver starts slamming the brakes immediately, the car moves by uniformly decelerated motion, so we can use the following relationship
(1)
where
a is the deleceration
S is the distance covered after a time t
is the velocity at time t
is the initial speed of the car
The accident is 80 m ahead of the car, so the minimum deceleration required to avoid the accident is the value of a such that S=80 m and
(the car should stop exactly at S=80 m to avoid the accident). Using these data, we can solve the equation (1) to find a:
And the negative sign means it is a deceleration.
where
a is the deleceration
S is the distance covered after a time t
The accident is 80 m ahead of the car, so the minimum deceleration required to avoid the accident is the value of a such that S=80 m and
And the negative sign means it is a deceleration.
Answer:
X = 5.44 m
Explanation:
First we can calculate the normal force acting from the floor to the ladder.
W₁+W₂ = N
W1 is the weigh of the ladder
W2 is the weigh of the person
So we have:
The friction force is:
Now let's define the conservation of torque about the foot of the ladder:
Solving this equation for X, we have:
Finally, X = 5.44 m
Hope it helps!
Answer:
The tension experienced in the string at the highest point is approximately 9.019 Newtons
Explanation:
The mass of the body tied to the string, m = 0.1 kg
The path of motion of the mass = Vertical circular motion
The speed of rotation of the stone, v = 10 m/s
The radius of the circular motion path, r = 1 m
The required information = The tension at the highest point, T
At the highest point, the tension, 'T', comprises of the centrifugal force, 'F', acting upwards in the string and the weight, 'W' of the body acting downwards
∴ T = F - W
Weight, W = m × g
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
Therefore;
The centrifugal force, F = 0.1 kg × (10 m/s)²/(1 m) = 10 N
The weight of the mass tied to the string, W ≈ 0.1 kg × 9.81 m/s² = 0.981 N
From which we have;
T = 10 N - 0.981 N = 9.019 N
The tension experienced in the string at the highest point ≈ 9.019 Newtons