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3 years ago

Find the point estimate for the true difference between the given population means.

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

3 0

Answer:

0.9 grams

Step-by-step explanation:

The point estimate for the average weight of Soap Bar A is:

$A=\frac{121+122+124+ 123+ 120+ 124+ 121+ 121+ 121+ 123+ 120}{11}\\A=121.82\ grams$

The point estimate for the average weight of Soap Bar B is:

$B=\frac{121+120+122+ 119+ 121+ 122+ 122+ 120+ 120 +121+ 122+123+119}{13}\\B=120.92\ grams$

Therefore, the point estimate for the true difference between the given population means is:

$Dif = A-B\\Dif = 121.82-120.92\\Dif=0.9\ grams$

The point estimate for the difference is 0.9 grams.

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Prove the trigonometric identity

Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

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Lets solve the bottom most part first:

$1-\frac{1}{1-sec^2x} \\\\$

Take LCM

$1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}$

now break the LCM

$\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1$

because 1/tan = cot x

and furthermore,

$cot^2x+1\\cosec^2x$

now we solve the above part and replace the bottom most part that we solved with $cosec^2x$

$\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x$

Hence proved! :D

4 0

2 years ago

Solve for q. a=qb+r What is q equal to? q=a−r−b q=a−r/b q=a/b −r q=a/rb

Mademuasel [1]

The given equation is $a=qb+r$

We need to solve the equation for q.

Value of q:

The value of q can be determined by solving the equation $a=qb+r$ for q.

Thus, subtracting both sides of the equation by r, we get;

$a-r=qb$

Now, dividing both sides of the equation by b, we have;

$\frac{a-r}{b}=\frac{qb}{b}$

Simplifying the terms, we get;

$\frac{a-r}{b}=q$

Therefore, the value of q is $q=\frac{a-r}{b}$

Hence, Option B is the correct answer.

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Alex17521 [72]

I think is 2x+y=-5 the answer

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chegg evaluate the following integral using trigonometric substitution. dx/square root(x^2-81), x > 9

vesna_86 [32]

Integration will be ln | ( x /9 ) + ( $\sqrt{(x/9)^{2} - 1 }$ ) | + c .

Given ∫ 1 dx / ( $x^{2}$ - 81 )

Put ,

x = 9 secθ

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and

$\sqrt{x^{2} - 9^{2} }$ = 9 tanθ

Substituting values in ∫ 1 dx / ( $x^{2}$ - 81 ) ,

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= ln | ( x /9 ) + ( $\sqrt{(x/9)^{2} - 1 }$ ) | + c

Hence , the integration will be ln | ( x /9 ) + ( $\sqrt{(x/9)^{2} - 1 }$ ) | + c .

To learn more on integration follow link :

brainly.com/question/20156869

#SPJ4

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