Answer: 0.56 m/s
Explanation:
Hi, to answer this question we have to apply the formula of the conservation of momentum.
m1 v1 = m2 v2 (because the system is stationary at the beginning)
Where:
m1 = mass of the astronaut
v1= velocity of the astronaut
m2= mass of the satellite
v2= velocity of the satellite
Replacing with the values given and solving:
86 kg (2.35m/s) = 360 kg v2
202.1 kgm/s=360kg v2
202.1kgm/s /360kg =v2
v2 = 0.56 m/s
Feel free to ask for more if needed or if you did not understand something.
Answer:
60 kg
Explanation:
An astronaut weighs 588 N on the earth
He also weighs 98 N on the moon
Therefore the the mass of the astronaut on the moon can be calculated as follows
= 588/98
= 6 × 10
= 60 kg
Hence the mass of the astronaut on the moon is 60 kg
True the only way to emit ur proton is if there are ground electrical
Increase because the mass of an object aligns with its weight
You have said that 15cm³ of gold weighs 2.8N. So I may infer that each cm³
of gold weighs about 0.19N. When I compare that figure with the 0.13N per cm³
of mercury, it becomes immediately apparent that the gold is more dense than
mercury. Therefore, the sample of gold, no matter what its size or weight, will
displace its total volume of mercury, and will go on to sink entirely beneath the
waves in the mercury.