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3 years ago

If the mass of an object is doubled, its gravitational force will:

Physics

2 answers:

Radda [10]3 years ago

7 0

Answer:

A. increase

Explanation:

tankabanditka [31]3 years ago

5 0

Increase because the mass of an object aligns with its weight

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A 17-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 33 N. Starting from rest, the sle

ycow [4]

Answer:

$\mu=0.185$

Explanation:

From the question we are told that:

Mass $m=17kg$

Force $F=33N$

Velocity $v=1.6m/s$

Distance $d= 9.8m$

Generally the equation for Work done is mathematically given by

$W=\triangle K.E+\triangle P.E$

Where

$\triangle K.E=(F-F_f)*2$

$F_f=F+\frac{\triangle K.E}{d}$

$F_f=33+\frac{0.5*17*1.6^2}{9.8}$

$F_f=30.8N$

Since

$f = \mu*m*g$

$\mu= 30.8/(m*g)$

$\mu= 30.8/(17*9.81)$

$\mu=0.185$

4 0

2 years ago

20. Threshold braking in the vehicle's braking system

amm1812

The answer is b hope this helps

7 0

3 years ago

Newton's third law says that for every action force there is a reaction force which is

olga nikolaevna [1]

A. Equal and opposite For every action, there is an equal and opposite reaction

4 0

3 years ago

You are In-line skates at the top of a small hill. Your potential energy is equal to 1000 J. The last time we checked, your mass

stira [4]

A) Weight = mass × acceleration (due to gravity)

= 60×9.8

= 588 N

B) Potential energy = mass x gravity x change in height

1,000 = 60.0 x 9.8 x h

h = 1.7 m

C) Kinetic energyF = potential energyI

KEF = 1/2mv2

PEI = mgh = 1,000 J

1/2mv2 = 1,000

1/2(60.0)v2 = 1,000

v2 = 33.33

v = 5.77 m/s

3 0

3 years ago

If Star A is magnitude 1.0 and Star B is magnitude 9.6 , which is brighter and by what factor?

ludmilkaskok [199]

Answer:

Star A is brighter than Star B by a factor of 2754.22

Explanation:

Lets assume,

the magnitude of star A = m₁ = 1

the magnitude of star B = m₂ = 9.6

the apparent brightness of star A and star B are b₁ and b₂ respectively

Then, relation between the difference of magnitudes and apparent brightness of two stars are related as give below: $(m_{2} - m_{1}) = 2.5\log_{10}(b_{1}/b_{2})$

The current magnitude scale followed was formalized by Sir Norman Pogson in 1856. On this scale a magnitude 1 star is 2.512 times brighter than magnitude 2 star. A magnitude 2 star is 2.512 time brighter than a magnitude 3 star. That means a magnitude 1 star is (2.512x2.512) brighter than magnitude 3 bright star.

We need to find the factor by which star A is brighter than star B. Using the equation given above,

$(9.6 - 1) = 2.5\log_{10}(b_{1}/b_{2})$

$\frac{8.6}{2.5} = \log_{10}(b_{1}/b_{2})$

$\log_{10}(b_{1}/b_{2}) = 3.44$

Thus,

$(b_{1}/b_{2}) = 2754.22$

It means star A is 2754.22 time brighter than Star B.

3 0

3 years ago