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seropon [69]
3 years ago
14

An astronaut, of total mass 86.0 kg including her suit, stands on a spherical satellite of mass 360 kg, both at rest relative a

nearby space station. She jumps at a speed of 2.35 m/s directly away from the satellite, as measured by an observer in the station. At what speed does that observer measure the satellite traveling in the opposite direction?
Physics
1 answer:
Afina-wow [57]3 years ago
5 0

Answer: 0.56 m/s

Explanation:

Hi, to answer this question we have to apply the formula of the conservation of momentum.

m1 v1 = m2 v2 (because the system is stationary at the beginning)

Where:

m1 = mass of the astronaut

v1= velocity of the astronaut

m2= mass of the satellite

v2= velocity of the satellite

Replacing with the values given and solving:

86 kg (2.35m/s) = 360 kg v2

202.1 kgm/s=360kg v2

202.1kgm/s /360kg =v2

v2 = 0.56 m/s

Feel free to ask for more if needed or if you did not understand something.

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Difference between friction and gravity<br>​
diamong [38]

Explanation:

Friction

Resistance defines friction. Friction consists of the resistance of one object in relation to another object with which it is in contact. Thus, friction is the force that opposes sliding motion, explains the Cornell Center for Materials Research. An example of friction involves removing a stain from clothing. You place detergent on a stained shirt, then repeatedly slide part of the shirt against the stained section. The friction eliminates the stain from the shirt.

Gravity

Gravity is simply defined as what goes up must come down. Gravity is the natural force exerted between two objects, drawing them toward each other. Therefore, instead of an object such as an apple thrown in the air staying there or floating, it falls down. Weight is extremely important to gravity. Gravity always exerts a force equal to the weight of the object it is acting on. A cup remains on a table because the upward force of the table is equal to the weight of the cup, causing it to stay in place.

<h2>hope it helps</h2>

brainliest please

5 0
2 years ago
If a ????=87.5 kgm=87.5 kg person were traveling at ????=0.900????v=0.900c , where ????c is the speed of light, what would be th
Diano4ka-milaya [45]

Answer:

\frac{K.E_r}{K.E}=2.875

Explanation:

Given:

mass, m = 87.5kg

Velocity, V = 0.900c

now,

the relativistic kinetic energy id given as:

K.E_r=(\gamma-1)mc^2 ...........(1)

where,

\gamma = relativistic factor, given as; \gamma=\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}

Now, the classical kinetic energy is given as:

K.E = \frac{1}{2}mv^2    ..........(2)

Dividing the equation (1) by (2) we get

\frac{K.E_r}{K.E}=\frac{(\gamma-1)mc^2}{\frac{1}{2}mv^2}

or

\frac{K.E_r}{K.E}=\frac{(\gamma-1)c^2}{\frac{1}{2}v^2}

substituting the values in the equation we get,

\frac{K.E_r}{K.E}=\frac{(\frac{1}{\sqrt{1-\frac{(0.90c)^2}{c^2}}}-1)c^2}{\frac{1}{2}\times(0.90c)^2}

or

\frac{K.E_r}{K.E}=2.875

5 0
3 years ago
An object with a mass of 32 kg has an initial energy of 500 J. At the end of the experiment, the velocity of the object is recor
Nezavi [6.7K]

Explanation:
the concept of conservation of the mechanical nerve
initial
Em₀ = 500 J
The energy is totally kinetic
Em₀ = K = ½ m v₀²
v₀ =
v₀ = √ (2 500/32)
v₀ = 5.59 m / s
v² = v₀² - 2 a x
the negative sign is because its stopping
a =
a = (5.59² - 5.1²) / 2 50
a = 0.0524 m / s²
Newton's second law
F = ma
F = 32 0.0524
F = 1.68 N
3 0
3 years ago
Suppose that the terminal speed of a particular sky diver is 165 km/h in the spread-eagle position and 320 km/h in the nosedive
coldgirl [10]

Answer:

3.76

Explanation:

We are given that

Terminal speed in the spread -eagle position,v_t=165 km/h

Terminal speed in the nosedive position,v'_t=320km/h

We have to find the ratio of the effective cross-sectional area A in the slower position to that in the faster position.

We  know that

Area, A=\frac{2mg}{C\rho v^2_t}

A_{slower}=\frac{2mg}{C\rho(165)^2}

A_{faster}=\frac{2mg}{C\rho(320)^2}

\frac{A_{slower}}{A_{faster}}=\frac{(320)^2}{(165)^2}

\frac{A_{slower}}{A_{faster}}=3.76

3 0
3 years ago
Read 2 more answers
According to the nfpa, the upper human survivability limit is approximately:
wolverine [178]

The National Fire Protection Association (NFPA) states that the furthest reaches of human temperature viability is 212°F, well beneath temperatures found in most noteworthy structure fires that are past the development (early) stage. In the present fire conditions, temperatures higher than 500°F can be effortlessly gotten inside three to four minutes. Flashover, which happens at roughly 1,100°F, can grow well under five minutes.2 If a space isn't legitimate for firefighters, caught casualties aren't probably going to survive either. Set aside the opportunity to make it safe and keep your firefighters from going for broke.

 

<span>60% of the casualties were found to have been presented to warm (most at temperatures over 200°F; some were beneath) and mugginess for six to seven minutes (remote from the fire range).</span>

5 0
3 years ago
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