What is the centripetal acceleration of a ball on a string that is whirled horizontally over a boy’s head? The radius of the cir
2 answers:
Answer:
Centripetal acceleration of boy on a string is 47.02 m/s²
Explanation:
It is given that,
Radius of the circle, r = 1.8 m
Speed of the ball, v = 9.2 m/s
Centripetal acceleration is given by :
Hence, the centripetal acceleration of a ball on a string that is whirled horizontally over a boy’s head is 47.02 m/s²
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Answer:
Explanation:
The best way to do this is to remember the rule about the halfway mark in a parabolic path. At a trajectory's half way point in its travels, it will be at its max height. To get the total time in the air, we take that time at half way and double it. Here's what we know that we are told:
initial velocity is 20 m/s
Here's what we know that we are NOT told:
a = -9.8 m/s/s and
final velocity is 0 at an object's max height in parabolic motion.
We will use the equation:
where v is final velocity and v0 is initial velocity. Filling in:
0 = 20 + (-9.8)t and
-20 = -9.8t so
t = 2 seconds. The stone reaches its max height 2 seconds after it is thrown; that means that after another 2 seconds it will be on the ground. Total air time is 4 seconds.