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Svetllana [295]
3 years ago
6

Which colligative property is employed when salt is put on an icy sidewalk to melt ice?

Chemistry
2 answers:
Iteru [2.4K]3 years ago
6 0
<span>For this number, we are to determine the colligative property that is affected by the addition of salt in the sidewalk in order to melt the ice. The answer is that the colligative property being displayed is the freezing point depression. Colligative properties are innate properties of substances and are only dependent on the amount of substance being added. </span>
ankoles [38]3 years ago
4 0
<span>The correct answer is 'freezing point depression'. Colligative properties depend on the concentration of molecules of a solute. Examples of other colligative properties are boiling point elevation or vapour pressure lowering. The salt causes ice on the side walk to melt because it lowers the freezing point. </span>
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An atom of a particular element is traveling at 1.00% of the speed of light. The de Broglie wavelength is found to be 3.31 × 10-
ExtremeBDS [4]

Answer:

The given atom is of Ca.

Explanation:

Given data:

Speed of atom = 1% of speed of light

De-broglie wavelength = 3.31×10⁻³ pm (3.31×10⁻³ / 10¹² = 3.31×10⁻¹⁵ m)

What is element = ?

Solution:

Formula:

m = h/λv

m = mass of particle

h  = planks constant

v = speed of particle

λ = wavelength

Now we will put the values in formula.

m = h/λv

m = 6.63×10⁻³⁴kg. m².s⁻¹/3.31×10⁻¹⁵ m ×( 1/100)×3×10⁸ m/s

m = 6.63×10⁻³⁴kg. m².s⁻¹/ 0.099×10⁻⁷m²/s

m = 66.97×10⁻²⁷ Kg/atom

or

6.69×10⁻²⁶ Kg/atom

Now here we will use the Avogadro number.

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

Now in given problem,

6.69×10⁻²⁶ Kg/atom × 6.022 × 10²³ atoms/ mol × 1000 g/ 1kg

40.3×10⁻³×10³g/mol

40.3  g/mol

So the given atom is of Ca.

8 0
3 years ago
In a science lab, a student heats up a chemical from 10 °C to 25 °C which requires thermal energy of 30000 J. If mass of the obj
olganol [36]

Answer:

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

Explanation:

Step 1: Data given

Initial temperature = 10.0 °C

Final temperature = 25.0 °C

Energy required = 30000 J

Mass of the object = 40.0 grams

Step 2: Calculate the specific heat capacity of the object

Q = m* c * ΔT

⇒With Q = the heat required = 30000 J

⇒with m = the mass of the object = 40.0 grams

⇒with c = the specific heat capacity of the object = TO BE DETERMINED

⇒with ΔT = The change in temperature = T2 - T2 = 25.0 °C - 10.0°C = 15.0 °C

30000 J = 40.0 g * c * 15.0 °C

c = 30000 J / (40.0 g * 15.0 °C)

c = 50 J/g°C

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

3 0
3 years ago
What is calculated by dividing mass volume
dem82 [27]
By dividing mass with volume, you will end up with density
7 0
3 years ago
Through which of the following ways can heat be transferred?
SashulF [63]

Answer:

The correct option is:

A) by direct or indirect contact between objects at different temperatures

Explanation:

Heat can be transferred in three different methods:

Conduction, Convection and Radiation

Conduction is heat transfer through direct contact between substances at different temperatures.

Convection is the heat transfer which takes place through air currents.

Radiation is the heat transfer that does not require contact between two objects.

Hence, heat transfer can take place through direct or indirect contact between objects at different temperatures.

4 0
3 years ago
How many protons and electrons in Arsenic ion
kow [346]
Protons=33 / electrons:42

3 0
3 years ago
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