It's quite strong and has a weak base . it would probably dissolve and the ph would drop
Answer:
0
Explanation:
Given parameters:
Half-life = 8.08days
Unknown:
What fraction is left unchanged after 16.16days = ?
Solution:
The half - life of a substance is the time taken for the half of a radioactive material to decay to half.
Day 0 Day 8.08 Day 16.16
100% 50% 0% Parent
0% 50% 100% Daughter
After 16.16 days, non of the original sample will remain unchanged.
The effect of an insoluble impurity, such as sand, on the observed melting point of a compound would be none. It will not depress or elevate the melting point of the compound. Instead, it would affect the reading if you are trying to determine the melting point of the compound. This is because you might be missing the actual melting point of the compound since you will be waiting for the whole sample to liquify. You would not be able to determine exactly that temperature because of the insoluble impurity would have a different melting point than that of the compound.
Answer:
c) FAD is the oxidizing agent
Explanation:
The β-oxidation is a catabolic process where fatty acids are degraded into a final product: Acetil-CoA. In order this process occurres, the fatty acid chain is being removed from a pair of carbon atoms on each cycle
Before the β-oxidation takes place, the fatty acid molecule should be activated, so it can go through the mitochondrial membrane into (via a carnitine translocator)
Once the activated molecule is inside the mitochondrial matrix, it can go through the β-oxidation: the first step is the oxidation of the fatty acid, with the enzyme Acyl-CoA-dehydrogenase (this enzyme catalyzes the creation of a double bond between carbon-2 and carbon-3.
This enzyme has attached a coenzyme: FAD, which takes the electrons (from the fatty acid oxidation) and becomes a reduced component: FADH2:
Acyl-CoA + FAD ↔ trans-Δ2-enoyl-CoA + FADH2
Answer:
139.11 grams
Explanation:
The molarity (M) is equal to m (moles) /L (liters).
Notice how it is in mL so converting it would be 0.75 L (750*10-3)
Now plug in the information
1.75=m/0.75
m=1.3125
Now m is in moles so convert to grams to get the mass
1.3125 mol Na2CO3 * 105.9888 g Na2CO3 = 139.1103
