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Virty [35]
3 years ago
15

One of the assumptions underlying the theory of control charting is that successive plotted points are independent of one anothe

r. Each plotted point can signal either that a manufacturing process is operating correctly or that there is some sort of malfunction. Even when a process is running correctly, there is a small probability that a particular point will signal a problem with the process. Suppose that this probability is 0.07. What is the probability that at least one of 10 successive points indicates a problem when in fact the process is operating correctly
Mathematics
1 answer:
aksik [14]3 years ago
4 0

Answer:

P(at least 1 wrong in 10) =0.5160

Step-by-step explanation:

Let A be the event  that there is a problem in the proces. Then the probability of problem with the process is P ( A) = 0.07

Let B be the event  that the process is without the problem. Then the probability of without problem is P ( B) = 0.93

Now we want to find the 10 successive points of event B. Since the events are independent we can find this as

P(B)+P(B)+P(B)+P(B)+P(B)+P(B)+P(B)+P(B)+P(B)+P(B)

or

P(B)^ 10= .93^10=0.48398

As we have to calculate at least 1 in 10 then we will subtract it from 1.

P(at least 1 wrong in 10) = = 1 - .93^10 =1- 0.48398=0.5160

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Answer:

a

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b

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c

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.          

Step-by-step explanation:

From the question we are told we are told that  

   The  equation for the temperature of a cup of coffee place on a counter is

         H= f(t)

Here  t is the time in minutes the  coffee was put on the counter

Generally  f(t)'  is the derivative of  f(t) at it represents the change of the temperature of the cup of coffee with respect to time

 Generally for the coffee placed on the counter after a couple of minutes the temperature will decrease hence  f(t)' is  negative

Generally the unit of the temperature is in degrees Celsius while that of time is  in minutes

  So the change in temperature with time f(35)' will be in degrees Celsius/minutes (i.e  degC/min)

  From the question we are told that

        |f(35)'| =  1.5

i.e  the rate of change of temperature after 35 minutes is  1.5

and

         |f(35)| =  68

i.e the temperature of the cup of coffee after 35 minutes is  67 degC

Now after another   t=  30  seconds =  \frac{30}{60}= 0.5 \ minutes the  rate  of change of the temperature of the cup of  coffee is  

          R =  |f(35)'| *  t

=>        R = 1.5  *  0.5

=>        R = 0.75    

So

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.  

     

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