6n/6=2/6
n=0.333333…
Or rounded to 0.3 in decimal form and 1/3 in fraction form
The first thing you want to do is plug in x and y into both equations:
a(3) + b(4) = 4
b(3) + a(4) = 8
rearrange to line up a’s and b’s
3a + 4b = 4
4a + 3b = 8
now you want to choose a or b and multiply each equation by a number to make them have the same amount of a’s or b’s.
4(3a + 4b = 4) = 12a + 16b = 16
3(4a + 3b = 8) = 12a + 9b = 24
Now we subtract the bottom equation from the top and solve for b:
12a + 16b - (12a + 9b) = 16 - 24
7b = -8
b = -8/7
Now we plug back in for b to one of the original equations:
3a + 4(-8/7) = 4
3a + (-32/7) = 4
3a - (32/7) = 4
3a = 4 + (32/7)
3a = (28/7) + (32/7)
3a = 60/7
a = (60/7)/3 = 20/7.
Finally, plug a and b in together to double check using the second equation.
4a + 3b = 8
4(20/7) + 3(-8/7) = ?
(80/7) - (24/7) = ?
56/7 = 8.
Answer:
HI = 8
TU = 45
Step-by-step explanation:
→ Find the scale factor enlargement
45 ÷ 10 = 4.5
→ Multiply JI by the scale factor to find it
10 × 4.5 = 45
→ Divide UV by the scale factor to find it
36 ÷ 4.5 = 8
It’s E :) it’s up 20 characters
The two containers hold 328 ounces at the they hold same amount of water.
<u>Step-by-step explanation:</u>
The equations below model the ounces of water, y, in each container after x minutes.
At the time after the start when the containers hold the same amount of water, the two equations must be equal.
⇒ 
The first step is to divide everything by 2 to make it simplified.
⇒ 
Now put everything on the left
.
Add the like terms together to further reduce the equation
Factorizing the equation to find the roots of the equation.
Here, b = -12 and c = -28
where,
- b is the sum of the roots ⇒ -14 + 2 = -12
- c is the product of the roots ⇒ -14 × 2 = -28
- Therefore, (x-14) (x+2) = 0
- The solution is x = -2 or x = 14
Take x = 14 and substitute in any of the given two equations,
⇒ 
⇒ 
⇒ 328 ounces
∴ The two containers hold 328 ounces at the they hold same amount of water.
