X3+6x2+6x+5 : x2+x+1

1 answer:

7 0

I am assuming this was the question you want answered
3x+6x^2+6x+5 = 2x+x+1
First you would combine all like terms on both sides. Start with the numbers with x
3x+6x= 9x
2x+x= 3x
Now multiply 6*2
6*2= 12

Now you have you have
9x+12+5 = 3x+1

Now combine 12+5
12+5=17

Now you have
9x+17 = 3x+1

Now subtract 1 from both sides
9x+17 = 3x+1
 -1 -1
9x+16 = 3x+0

Now subtract 9x from both sides
9x+16 = 3x+0
-9x -9x
0+16 = -6x

Now divide -6 by both sides
16 = -6x
---- ----
6 6

The final answer is 2 2/3 = x or 2.66666 = x

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Answer:

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Explanation:

If you are given a function that is defined by a system of equations associated with certain intervals of x, just find which interval makes x true, and then substitute x into the equation of that interval.

For example, given g(-4), this is an expression which is asking for the value of the equation when x = -4. So -4 is not ≥ 2, so ¼x - 1 will not be used. -4 is also not ≤ -1 and ≤ 2, so -(x - 1)² + 3 will not be used either. So in turn, we will just use -1 which is always -1 so g(-4) will just be -1, right because there is no x variable in -1 so it will always be the same.

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Step-by-step explanation:

Before, we go on to check these relations for the desired properties, let us define what it means for a relation to be reflexive, symmetric or transitive.

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