The period of the pendulum is given by the following equation
T = 2π * sqrt (L/g)
Where g is the gravity (free fall acceleration)
L is the longitude of the pendulum
T is the period.
We find g.............> (T /2π)^2 = L/g
g = L/(T /2π)^2...........> g = 22.657 m/s^2
Cathode Ray Tube i think?
Use the equation q=mc/\T, where q is the heat lost, m is mass, and /\T is the change in temperature, and c is the specific heat.
q=50kg(3470J/kg K)(2K)
q=<span>347000 J
Any other questions, just ask.
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Explanation: Formulas you need to use:
K=0.5mass(Velocity^2)
km/h / 3.6 ===>M/S
Step 1:
convert km/h to m/s
Put the values in the formula :
They are all classified in the same kingdom
