1) % = (Wo /Wi) * 100
Solve for Wo => Wo = (% / 100) * Wi
For example, % =30% and Wi = 250 => Wo = (30 /100) * 250 = 0.30 * 250 = 75
Wo = 75
2) % = (Wo / Wi) * 100
Solve for Wi
=> Wi = Wo * (%/100)
For example, Wo = 125 and % = 40%
=> Wi = 125 * (40 / 100) = 125 * 0.40 = 50
Wi = 50
It is electrical energy into connected energy has in relation to the question
Answer:
a) 1.5 × 10² kPa
b) 16.9/8.1
Explanation:
a) The pressure of the front tires is 22 psi. The appropriate conversion factor is 1 psi = 6.89 kPa. The pressure of the tires in kPa is:
22 psi × (6.89 kPa / 1 psi) = 1.5 × 10² kPa
b) Regarding the blood pressure, the minimun reading is 61 mmHg and the maximum reading is 127 mmHg. The appropriate conversion factor is 1 kPa = 7.50 mmHg. The blood pressure in kPa is:
61 mmHg × (1 kPa / 7.50 mmHg) = 8.1 kPa
127 mmHg × (1 kPa / 7.50 mmHg) = 16.9 kPa
Answer:
Taking it was dropped with inital velocity of 0m/s.
v = u+at
v = 0 + 9.8*1.5
v = 14.7s
(a=9.8m/s^2 << That's the acceleration due to gravity)
Explanation:
Answer:
2 more neutrons
Explanation:
To obtain the answer to the question, let us calculate the number of neutrons in carbon–14 and standard carbon (i.e carbon–12). This can be obtained as follow:
For carbon–14:
Mass number = 14
Proton number = 6
Neutron number =?
Mass number = Proton + Neutron
14 = 6 + Neutron
Collect like terms
14 – 6 = Neutron
8 = Neutron
Neutron number = 8
For carbon–12:
Mass number = 12
Proton number = 6
Neutron number =?
Mass number = Proton + Neutron
12 = 6 + Neutron
Collect like terms
12 – 6 = Neutron
6 = Neutron
Neutron number = 6
SUMMARY:
Neutron number of carbon–14 = 8
Neutron number of carbon–12 = 6
Finally, we shall determine the difference in the neutron number. This can be obtained as follow:
Neutron number of carbon–14 = 8
Neutron number of carbon–12 = 6
Difference =?
Difference = (Neutron number of carbon–14) – (Neutron number of carbon–12)
Difference = 8 – 6
Difference = 2
Therefore, carbon–14 has 2 more neutrons than standard carbon (i.e carbon–12)
