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3 years ago

When current increases and resistance remains constant what must happen to voltage?

Physics

1 answer:

UNO [17]3 years ago

7 0

Answer:

Explanation:

Because V =IR.. So as the voltage incrraees cureent must increase

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A pump can throw a stream of water up to 29.6m. What is the initial speed of the stream when it leaves a hose nozzle.

zhannawk [14.2K]

Hello
We know that the water's kinetic energy upon leaving will be converted into potential energy as it is projected straight up. The maximum height attained by the water is 29.6m.
We know Kinetic Energy is
1/2 * m * v^2
And Potential energy is
m*g*h
Equating,
(m*v^2)/2 = m*g*h
The mass cancels out from each side, making an object's mass irrelevant when its Kinetic and Potential energies are interchanging.
v = sprt(2gh)
v = sqrt(2*9.81*29.6)
v = 24.1 m/s

7 0

3 years ago

Name one material through which continuous flow of charge can be produced from heat energy

Arlecino [84]

Answer:

A continuous flow of negative charges (electrons) creates an electric current. The pathway taken by a electric current is a circuit.

Explanation:

6 0

3 years ago

Read 2 more answers

A circular loop of flexible iron wire has an initial circumference of 164cm , but its circumference is decreasing at a constant

Travka [436]

Answer:

emf = 0.02525 V

induced current with a counterclockwise direction

Explanation:

The emf is given by the following formula:

$emf=-\frac{\Delta \Phi_B}{\Delta t}=-B\frac{\Delta A}{\Delta t}$ $\ \ =-B\frac{A_2-A_1}{t_2-t_1}$ (1)

ФB: magnetic flux = BA

B: magnitude of the magnetic field = 1.00T

A2: final area of the loop; A1: initial area

t2: final time, t1: initial time

You first calculate the final A2, by taking into account that the circumference of loop decreases at 11.0cm/s.

In t = 4 s the final circumference will be:

$c_2=c_1-(11.0cm/s)t=164cm-(11.0cm/s)(4s)=120cm$

To find the areas A1 and A2 you calculate the radius:

$r_1=\frac{164cm}{2\pi}=26.101cm\\\\r_2=\frac{120cm}{2\pi}=19.098cm$

r1 = 0.261 m

r2 = 0.190 m

Then, the areas A1 and A2 are:

$A_1=\pi r_1^2=\pi (0.261m)^2=0.214m^2\\\\A_2=\pi r_2^2=\pi (0.190m)^2=0.113m^2$

Finally, the emf induced, by using the equation (1), is:

$emf=-(1.00T)\frac{(0.113m^2)-(0.214m^2)}{4s-0s}=0.0252V=25.25mV$

The induced current has counterclockwise direction, because the induced magneitc field generated by the induced current must be opposite to the constant magnetic field B.

4 0

3 years ago

I WILL MARK BRAINLIEST!

xxMikexx [17]

Answer:

Explanation:

The answer is C

7 0

3 years ago

A stuffed toy with a mass of 0.900 kilograms sits on the edge of a bed at a height of 0.830 if the toy falls off the bed what wi

Olenka [21]

Mechanical energy (ME) is the sum of potential energy (PE) and kinetic energy (KE). When the toy falls, energy is converted from PE to KE, but by conservation of energy, ME (and therefore PE+KE) will remain the same.

Therefore, ME at 0.500 m is the same as ME at 0.830 m (the starting point). It's easier to calculate ME at the starting point because its just PE we need to worry about (but if we wanted to we could calculate the instantaneous PE and KE at 0.500 m too and add them to get the same answer).

At the start:

ME = PE = mgh
ME = 0.900 (9.8) (0.830)
ME = 7.32 J

8 0

3 years ago