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kozerog [31]
3 years ago
9

A planet in our solar system is located far from the sun describe the size and composition of the planet

Physics
2 answers:
Brilliant_brown [7]3 years ago
7 0
Well first we can tell that it will be very cold. For ex. Earth is fairly close to the sun. It gets pretty hot whenever the sun is out. Therefore we know being closer to the sun creates warmth on the planet.  And as you can see on the picture of the solar system I attached, it seems as if the planet gets bigger the further away from the sun. So I would appose cold and big. <span />

givi [52]3 years ago
4 0

Answer:

fjnclenfoc

Explanation:

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zalisa [80]

Answer:

If you apply a force to separate 2 opposite poles, the potential energy of the system increases.

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2 years ago
What is the average speed for the entire graph?
Maru [420]

Answer:

Explanation:

Divide the total distance traveled by the total time spent traveling. This will give you your average speed. . So if Ben traveled 150 miles in 3 hours, 120 miles in 2 hours, and 70 miles in 1 hour, his average speed was about 57 mph.

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if a train starts from rest and attains a velocity of 100m/s in 25 seconds. calculate the acceleration produced by the train.​
stira [4]
-4 km/s2

Explanation:
0-100/25
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-4
5 0
3 years ago
A trick shot archer shoots an arrow with a velocity of 30.0 m/s at an angle of 20.0 degrees with respect to the horizontal. An a
svlad2 [7]

Answer:

u'=10.259\ m.s^{-1} is the initial velocity of tossing the apple.

the apple should be tossed after \Delta t=0.0173\ s

Explanation:

Given:

  • velocity of arrow in projectile, v=30\ m.s^{-1}
  • angle of projectile from the horizontal, \theta=20^{\circ}
  • distance of the point of tossing up of an apple, d=30\ m

<u>Now the horizontal component of velocity:</u>

v_x=v\ cos\ \theta

v_x=30\times cos\ 20^{\circ}

v_x=28.191\ m.s^{-1}

<u>The vertical component of the velocity:</u>

v_y=v.sin\ \theta

v_y=30\times sin\ 20^{\circ}

v_y=10.261\ m.s^{-1}

<u>Time taken by the projectile to travel the distance of 30 m:</u>

t=\frac{d}{v_x}

t=\frac{30}{28.191}

t=1.0642\ s

<u>Vertical position of the projectile at this time:</u>

h=v_y.t-\frac{1}{2}g.t^2

h=10.261\times 1.0642-\frac{1}{2} \times 9.8\times 1.0642^2

h=5.3701\ m

<u>Now this height should be the maximum height of the tossed apple where its velocity becomes zero.</u>

v'^2=u'^2-2g.h

0^2=u'^2-2\times 9.8\times 5.3701

u'=10.259\ m.s^{-1} is the initial velocity of tossing the apple.

<u>Time taken to reach this height:</u>

v'=u'-g.t'

0=10.259-9.8\times t'

t'=1.0469\ s

<u>We observe that </u>t>t'<u> hence the time after the launch of the projectile after which the apple should be tossed is:</u>

\Delta t=t-t'

\Delta t=1.0642-1.0469

\Delta t=0.0173\ s

8 0
3 years ago
Q 6: A body throws a ball vertically up. It returns to the ground after 5 seconds. Find
Rasek [7]

Answer:

Taking gravity to be 9.8m/s2, The velocity is 24.5m/s2.

Taking gravity to be 10m/s2, The velocity is 25m/s2.

Explanation:

According the first formula of motion under the influence of gravity for upward motion, v=u-gt, where v=final velocity, u=initial velocity, and t= time taken.

Here the time taken for the ball to reach the maximum point is half of 5, which is 2.5 seconds.

And v is 0, since at the maximum point gravity slows down the velocity to 0.

Finding the initial velocity,

v=u-gt

0=u-10(2.5)

u=10(2.5)

u=25m/s

8 0
3 years ago
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