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2 years ago

A planet in our solar system is located far from the sun describe the size and composition of the planet

Physics

2 answers:

Brilliant_brown [7]2 years ago

7 0

Well first we can tell that it will be very cold. For ex. Earth is fairly close to the sun. It gets pretty hot whenever the sun is out. Therefore we know being closer to the sun creates warmth on the planet. And as you can see on the picture of the solar system I attached, it seems as if the planet gets bigger the further away from the sun. So I would appose cold and big. <span />

givi [52]2 years ago

4 0

Answer:

fjnclenfoc

Explanation:

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Blocks A and B are identical metal blocks. Initially block A is neutral, and block B has a net charge of 8.7 nC. Using insulatin

JulsSmile [24]

Explanation:

(a) Since, it is given that the blocks are identical so distribution of charge will be uniform on both the blocks.

Hence, final charge on block A will be calculated as follows.

Charge on block A = $\frac{(8.7 + 0 nC}{2}$

= 4.35 nC

Therefore, final charge on the block A is 4.35 nC.

(b) As it is given that the positive charge is coming on block A . This means that movement of electrons will be from A to B.

Thus, we can conclude that while the blocks were in contact with each other then electrons will flow from A to B.

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3 years ago

Read 2 more answers

A student walks 10 m North, 6 m South, 7 m West and 4 m East. Find the student's distance AND displacement

BlackZzzverrR [31]

Answer: Distance: 27m Displacement: 7m

Explanation: Distance is total, Displacement is from the start.

Hope this helped!

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5 0

3 years ago

What is the coefficient of friction between the skates and the ice?

natta225 [31]

The coefficient of friction is 0.051

Explanation:

The motion of the skater is a uniformly accelerated motion, therefore we can use the following suvat equation:

$v^2 - u^2 = 2as$

where:

v = 0 is the final velocity of the skater (he comes to a stop)

u = 10.0 m/s is his initial velocity

a is the acceleration

$s=1.0\cdot 10^2 m = 100 m$ is the distance he travels before stopping

Solving for a, we find the acceleration of the skater:

$a=\frac{v^2-u^2}{2s}=\frac{0-10.0^2}{2(100)}=-0.5 m/s^2$

We also know that the net force acting on the skater is the force of friction, therefore we can write (Newton's second law of motion):

$F= ma = -\mu mg$

where

$-\mu mg$ is the force of friction

m is the mass of the skater

$\mu$ is the coefficient of friction

$a=-0.5 m/s^2$ is the acceleration

$g=9.8 m/s^2$ is the acceleration of gravity

Solving for $\mu$ , we find the coefficient of friction:

$\mu = -\frac{a}{g}=-\frac{-0.5}{9.8}=0.051$

Learn more about friction:

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3 years ago

A block of mass 3kg is placed on a rough surface. The coefficient of static friction between two surfaces is 0.2 then what is th

yarga [219]

Answer:

the minimun horizontal force is = 5,88 N

Explanation:

Using a free body diagram we can calculate this force, in the image attached and using Newton's law we have:

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2 years ago

How will you charge a metal sphere by the process of induction?

zzz [600]

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3 years ago