<span>150000 seconds or approximately 1.7 days.
The equation for the orbital period is:
Ď„=âš((4Ď€^2/ÎĽ)a^3)
where
Ď„ = Period
ÎĽ = standard gravitational parameter (GM)
a = semi-major axis
It's generally better to use ÎĽ rather than the product of G and M since we know ÎĽ more accurately than either G or M in many cases from observations of satellites around the various planets. For instance in the case of Jupiter, we know ÎĽ is 1.26686534(9)Ă—10^17 whereas we only know it's mass at 1.8982x10^27 kg and G at 6.674x10^-11 m^3/(kg*s^2). Anyway, let's first calculate ÎĽ based upon the data given:
ÎĽ = 1.9x10^27 kg * 6.67ex10^-11 m^3/(kg*s^2)
ÎĽ = 1.26806x10^17 m^3/s^2
Now let's substitute the known values into the equation for the orbital period.
Ď„=âš((4Ď€^2/ÎĽ)a^3)
Ď„=âš((4Ď€^2/1.26806x10^17)(4.22x10^8)^3)
Ď„=âš((4*9.869604401/1.26806x10^17)(7.5151448x10^25)
Ď„=âš((39.4784176/1.26806x10^17)(7.5151448x10^25)
Ď„=âš((3.11329256x10^-16)(7.5151448x10^25)
Ď„=âš(2.3396844x10^10)
Ď„=152960.2706
Rounding to 2 significant figures since that's the precision of the least accurate datum, we get 150000 seconds, or approximately 1.7 days.</span>
Answer:
b
Explanation:
because it fly and you need for it to drop at the right spot for them to get it
Answer:
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Explanation:
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There's not enough information in the question to find the object's velocity. The best we can do is describe its speed.
The object's speed at the end of the 10.0 seconds =
<em>(its speed at the beginning of the 10.0 seconds)</em>
plus
<em>(10) </em>times<em> (the value of the acceleration) .</em>
<em></em>
The question is incomplete. Here is the entire question.
A jetboat is drifting with a speed of 5.0m/s when the driver turns on the motor. The motor runs for 6.0s causing a constant leftward acceleration of magnitude 4.0m/s². What is the displacement of the boat over the 6.0 seconds time interval?
Answer: Δx = - 42m
Explanation: The jetboat is moving with an acceleration during the time interval, so it is a <u>linear</u> <u>motion</u> <u>with</u> <u>constant</u> <u>acceleration</u>.
For this "type" of motion, displacement (Δx) can be determined by:
is the initial velocity
a is acceleration and can be positive or negative, according to the referential.
For Referential, let's assume rightward is positive.
Calculating displacement:
= - 42
Displacement of the boat for t=6.0s interval is = - 42m, i.e., 42 m to the left.
