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4 years ago

Where does digestion begin?

Mathematics

2 answers:

Nookie1986 [14]4 years ago

8 0

Answer:

Digestion begins in the mouth.

Step-by-step explanation:

it is believed that it starts from the mouth with the secretion of saliva and its digestive enzymes. Food is formed into a bolus by the mechanical mastication and swallowed into the esophagus from where it enters the stomach through the action of peristalsis.

Anna35 [415]4 years ago

3 0

Answer:

the digestion begins in the mouth

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Jocelyn estimates that a piece of wood measures 5.5 cm. If it actually measures 5.62, what is the percent error of Jocelyns esti

goldenfox [79]

Answer: The percent error is -2.1352% of Jocelyn's estimate.

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3 years ago

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Vera_Pavlovna [14]

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3 years ago

Read 2 more answers

Can someone help me find the perimeter and area of the shape or figure?

MA_775_DIABLO [31]

0.7 + 0.4 + 0.6 + 0.4 = 2.1 is the perimeter

0.7 x 0.4 = 0.28

0.6 x 0.4 = 0.24

0.28 + 0.24 = 0.52 is the area

Hope that helped!

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3 years ago

What is the nth term rule of the quadratic sequence below?

Vladimir [108]

Answer:

3n² + 5n - 2

Step-by-step explanation:

Given sequence:

6, 20, 40, 66, 98, 136, ...

Calculate the first differences between the terms:

$6 \underset{+14}{\longrightarrow} 20 \underset{+20}{\longrightarrow} 40 \underset{+26}{\longrightarrow} 66 \underset{+32}{\longrightarrow} 98 \underset{+38}{\longrightarrow} 136$

As the first differences are not the same, calculate the second differences:

$14 \underset{+6}{\longrightarrow} 20 \underset{+6}{\longrightarrow} 26 \underset{+6}{\longrightarrow} 32 \underset{+6}{\longrightarrow} 38$

As the second differences are the same, the sequence is quadratic and will contain an n² term.

The coefficient of the n² term is half of the second difference.

Therefore, the n² term is: 3n²

Compare 3n² with the given sequence:

$\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 & 3 & 12 & 27 & 48 \\\cline{1-5} \sf operation & +3&+8 & +13 & +18 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}$

The second operations are different, therefore calculate the differences between the second operations:

$3 \underset{+5}{\longrightarrow} 8 \underset{+5}{\longrightarrow} 13\underset{+5}{\longrightarrow} 18$

As the differences are the same, we need to add 5n as the second operation:

$\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 +5n & 8&22 & 42 & 68\\\cline{1-5}\sf operation & -2 &-2 &-2 & -2 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}$

Finally, we can clearly see that the operation to get from 3n² + 5n to the given sequence is to subtract 2.

Therefore, the nth term of the quadratic sequence is:

3n² + 5n - 2

6 0

2 years ago

What is the product? (7x2y^3)(3x^5=y^8)

spin [16.1K]

Answer:

is the equal sign supposed to be there? if it wasnt then answer would be 42x^6y^11

Step-by-step explanation:

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4 years ago