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solong [7]
3 years ago
11

You have deployed your Ethernet cable near a generator, whose heat is effecting the cable in a way that its energy is lost. If s

ignal has a power of 2 mW before passing near the generator and it becomes 1.4 mW after passing near the generator. How much is the attenuation
Computers and Technology
1 answer:
Naddik [55]3 years ago
8 0

Answer:

0.7

Explanation:

Atenuation is the loss of power of a signal.

Attenuation = output power/input power

                   = 1.4/2

                  = 0.7

You might be interested in
C++ code only
nordsb [41]

Using the computational language C++ it is possible to write a code is possible to create a function that stores items like this:

<h3>Writting the code in C++: </h3>

<em>//Header files</em>

<em>#include <iostream></em>

<em>#include <string></em>

<em>#include <fstream></em>

<em>using namespace std;</em>

<em>//Class inventoryItem</em>

<em>class inventoryItem</em>

<em>{</em>

<em>public:</em>

<em>//Variable declaration</em>

<em>string itemName;</em>

<em>string itemNumber;</em>

<em>double itemPrice;</em>

<em>int itemQuantity;</em>

<em>};</em>

<em>//implementation of menuItems() function.</em>

<em>void menuItems()</em>

<em>{</em>

<em>// Display the Menu</em>

<em>cout << "=============================\n";</em>

<em>cout << " 1) Add an item to memory\n"</em>

<em><< " 2) Search memory for an item \n"</em>

<em><< " 3) List what's in memory\n"</em>

<em><< " 4) Total value on hand\n"</em>

<em><< " 5) Save to a file\n"</em>

<em><< " 6) Read from a file\n"</em>

<em><< " 0) Exit Program" << endl;</em>

<em>}</em>

<em>//main method.</em>

<em>int main()</em>

<em>{</em>

<em>//variable declaration.</em>

<em>int mnuChoice, cn = 0, d;</em>

<em>string n;</em>

<em>double sum = 0, c;</em>

<em>int temp;</em>

<em>string a, b;</em>

<em>string inputBuffer;</em>

<em>inventoryItem items[100];</em>

<em>ifstream inventoryFile("inventory.txt");</em>

<em>if (inventoryFile)</em>

<em>{</em>

<em>//store the data from the file to memory.</em>

<em>while (!(inventoryFile.eof()))</em>

<em>{</em>

<em>inventoryFile >> items[cn].itemName;</em>

<em>inventoryFile >> items[cn].itemNumber;</em>

<em>inventoryFile >> inputBuffer;</em>

<em>items[cn].itemPrice = atof(inputBuffer.c_str());</em>

<em>inventoryFile >> inputBuffer;</em>

<em>items[cn].itemQuantity = atoi(inputBuffer.c_str());</em>

<em>cn++;</em>

<em>}</em>

<em>inventoryFile.close();</em>

<em>ifstream inventoryFile("inventory.txt");</em>

<em>ofstream fout;</em>

<em>fout.open("inventory.txt");</em>

<em>do</em>

<em>{</em>

<em>menuItems();</em>

<em>cout << cn << " items stored." << endl;</em>

<em>// Prompt and read choice form the user</em>

<em>cout << "Enter your choice: ";</em>

<em>cin >> mnuChoice;</em>

<em />

<em>switch (mnuChoice)</em>

<em>{</em>

<em>//Add a new inventory item to the data in memory.</em>

<em>case 1:</em>

<em>// Prompt and read name of the item from the user</em>

<em>cout << "Enter name of the item: ";</em>

<em>cin >> inputBuffer;</em>

<em>items[cn].itemName = inputBuffer;</em>

<em>// Prompt and read itemNumber from the user</em>

<em>cout << "Enter the itemNumber: ";</em>

<em>cin >> inputBuffer;</em>

<em>items[cn].itemNumber = inputBuffer;</em>

<em>// Prompt and read itemPrice from the user</em>

<em>cout << "Enter the itemPrice: ";</em>

<em>cin >> inputBuffer;</em>

<em>items[cn].itemPrice = atof(inputBuffer.c_str());</em>

<em>// Prompt and read itemQuantity from the user</em>

<em>cout << "Enter the itemQuantity: ";</em>

<em>cin >> inputBuffer;</em>

<em>items[cn].itemQuantity = atoi(inputBuffer.c_str());</em>

<em>cn++;</em>

<em>break;</em>

<em>//Search the inventory for an item by inventory number.</em>

<em>case 2:</em>

<em>temp = 0;</em>

<em>cout << "Enter inventory itemNumber: ";</em>

<em>cin >> n;</em>

<em>for (int i = 0; i < cn&&temp != 1; i++)</em>

<em>{</em>

<em>// If found, print the stored info</em>

<em>if (items[i].itemNumber.compare(n) == 0)</em>

<em>{</em>

<em>// Display the stored information</em>

<em>cout << "Item Name" << "\t" << "Item Number" << "\t" << " Item Price" << "\t" << " Item Quantity" << endl;</em>

<em>cout << items[i].itemName << "\t " << items[i].itemNumber << " \t" << items[i].itemPrice << "\t " << items[i].itemQuantity << endl;</em>

<em>temp = 1;</em>

<em>}</em>

<em>}</em>

<em>// otherwise print 'not found'.</em>

<em>if (temp == 0)</em>

<em>{</em>

<em>cout << "Not found!!!" << endl;</em>

<em>}</em>

<em>break;</em>

<em>//List the inventory on the screen</em>

<em>case 3:</em>

<em>cout << "The data in the memory is:" << endl;</em>

<em>cout << "Item Name" << "\t" << "Item Number" << "\t" << " Item Price" << "\t" << " Item Quantity" << endl;</em>

<em>for (int i = 0; i < cn; i++)</em>

<em>{</em>

<em>cout << items[i].itemName << "\t " << items[i].itemNumber << "\t " << items[i].itemPrice << " \t" << items[i].itemQuantity << endl;</em>

<em>}</em>

<em>break;</em>

<em>// Calculate the total value on hand.</em>

<em>case 4:</em>

<em>for (int i = 0; i < cn; i++)</em>

<em>{</em>

<em>// The sum is the accumulation of all the (quantities * prices).</em>

<em>sum += items[i].itemPrice*items[i].itemQuantity;</em>

<em>}</em>

<em>cout << "sum value on hand: " << sum << endl;</em>

<em>break;</em>

<em>// Save the inventory data in the given file</em>

<em>case 5:</em>

<em>for (int i = 0; i < cn; i++)</em>

<em>{</em>

<em>if (i == cn - 1)</em>

<em>{</em>

<em />

<em>fout << items[i].itemName << " \t" << items[i].itemNumber << " \t" << items[i].itemPrice << " \t" << items[i].itemQuantity;</em>

<em>}</em>

<em>else</em>

<em>{</em>

<em />

<em>fout << items[i].itemName << " \t" << items[i].itemNumber << " \t" << items[i].itemPrice << " \t" << items[i].itemQuantity << endl;</em>

<em>}</em>

<em>}</em>

<em>break;</em>

<em>// Read the data from the file</em>

<em>case 6:</em>

<em>while (!(inventoryFile.eof()))</em>

<em>{</em>

<em>inventoryFile >> a;</em>

<em>inventoryFile >> b;</em>

<em>inventoryFile >> inputBuffer;</em>

<em>c = atof(inputBuffer.c_str());</em>

<em>inventoryFile >> inputBuffer;</em>

<em>d = atoi(inputBuffer.c_str());</em>

<em>// Dsiplays the data in the file</em>

<em />

<em>cout << a << " " << b << " " << c << " " << d << endl;</em>

<em>}</em>

<em>break;</em>

<em>}</em>

<em>// Check the menu choice is not equal to 0,</em>

<em>//if it is equal exit from the loop</em>

<em>} while (mnuChoice != 0);</em>

<em>// File closed</em>

<em>fout.close();</em>

<em>inventoryFile.close();</em>

<em>}</em>

<em>// If the inventory file does not exist</em>

<em>// and then display the error message.</em>

<em>else</em>

<em>{</em>

<em>cout << "File does not exist!" << endl;</em>

<em>}</em>

<em />

<em>return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/17544466

#SPJ1

5 0
2 years ago
MIPS assembly language
maria [59]

Answer:

the answer is a t t i c

Explanation:

7 0
3 years ago
Java’s class Color has a constructor that takes three integers as parameters: the red, green, and blue components of the color
Tanzania [10]

Answer:

    public Balloon(){

          //Invokes the 2 argument constructor for balloon with relevant  

          //parameters

          this(10,new Color(135,206,250));

    }

Explanation:

class Balloon{

    //Private fields in the Balloon class

    private double radius = 0;

    private Color c = null;

    // Constructor with two arguments - radius and Color

    public Balloon(double radius,Color c){

         this.radius = radius;

         this.c = c;

    }

    // No argument constructor

    public Balloon(){

          //Invokes the 2 argument constructor for balloon with relevant  

          //parameters

          this(10,new Color(135,206,250));

    }

}

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4 years ago
Which of the follow is the best technique to determine how many menu items are needed and how to structure the menus and sub men
AnnZ [28]

Answer:

c. ​Group use cases by actor.

Explanation:

A use case is used to describe interaction between systems and users to achieve a goal. Mostly, a list of possible interaction between the system and the user is identified. The user can be a single person or a group. By using use case, the requirement of a systems is identified from a users point of view.

8 0
3 years ago
Which form of investigation aims at checking whether or not a target system is subject to attack based on a database of tests, s
VikaD [51]

Answer:

<em>Empirical technical </em>research has a fundamental objective, which is to provide objective and independent information on the quality of the product to the interested party or stakeholder. It is one more activity in the quality control process.

Explanation:

Testing is basically a set of activities within software development. Depending on the type of tests, these activities may be implemented at any time during said development process. There are different software development models, as well as test models. Each one has a different level of involvement in development activities.

In a full penetration testing process, there are pre-instances to run this tool, but to take the first steps it is probably the best way to start. Nmap is a network scanning tool that allows you to identify what services are running on a remote device, as well as the identification of active computers, operating systems on the remote computer, existence of filters or firewalls, among others.

In simple words, when a server or device is going to be attacked, the attacker can carry out different attacks depending on the service: it is not the same to damage a web server, a database server or a perimeter router. Therefore, in any deployment, the first step will be to identify the services in the infrastructure, to decide how to proceed and, considering that in a penetration test the steps of an attacker are “imitated”, it will also be started in the same way.

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