1 = 1 x 1
1 factors
2 = 1 x 2
2 factors
3 = 1 x 3
2 factors
4 = 1 x 4
4 = 2 x 2
3 factors
5 = 1 x 5
2 factors
6 = 1 x 6
6 = 2 x 3
4 factors
7 = 1 x 7
2 factors
8 = 1 x 8
8 = 2 x 4
4 factors
9 = 1 x 9
9 = 3 x 3
3 factors
10 = 1 x 10
10 = 2 x 5
4 factors
11 = 1 x 11
2 factors
12 = 1 x 12
12 = 2 x 6
12 = 3 x 4
6 factors
13 = 1 x 13
2 factors
14 = 1 x 14
14 = 2 x 7
4 factors
15 = 1 x 15
15 = 3 x 5
4 factors
16 = 1 x 16
16 = 2 x 8
16 = 4 x 4
5 factors
17 = 1 x 17
2 factors
18 = 1 x 18
18 = 2 x 9
18 = 3 x 6
6 factors
19 = 1 x 19
2 factors
20 = 1x 20
20 = 2 x10
20 = 4 x 5
6 factors
So they are 6, 8, 10, 14 and 15 on the number line
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
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Answer:
95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C
Step-by-step explanation:
The confidence interval for a proportion is given as [p +/- margin of error (E)]
p is sample proportion = 870/1,100 = 0.791
n is sample size = 1,100
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (z) at 5% significance level is 1.96.
E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024
Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767
Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815
95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.
Answer:
30 km/h car
Step-by-step explanation:
From analysis the car traveling at 30 km/h has greater kinetic energy
we can deduce it from the expression of kinetic energy which is

Assuming the mass m= 1 kg
For the 30 km/h

For the 15 km/h

Though the kinetic energy is a function of mass and velocity, but from our analysis the faster moving object has more KE
Substitute 22 for x
2(22)-5
44-5
39
Use the Pythagorean Theorem to find the diagonal of the rectangle.
The diagonal of the rectangle is the diameter of the circle.
Diameter (d) = 2 · radius (r)
Circumference (C) = 2· π · r → π · d