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4 years ago

The following statements regarding the exhaust gas recirculation (EGR) valve are all correct except:

Physics

1 answer:

elixir [45]4 years ago

7 0

Answer:

B. Some systems monitor EGR operation using a manifold absolute pressure (MAP) sensor.

Explanation:

The Manifold Absolute Pressure (MAP) sensor is a device used to measure absolute pressure inside the engine, it is used to calculate gas quantity needed to be injected into the cylinder and also for engine load input by the powertrain control module (PCM).

It is not used with the EGR as a monitor.

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On an essentially frictionless, horizontal ice rink, a skater moving at 5.0 m/s encounters a rough patch that reduces her speed

madreJ [45]

Answer:

The length of the rough patch is 4.345 meters.

Explanation:

According to the Work-Energy Theorem, change in kinetic energy is equal to the dissipated work due to friction. That is:

$K_{1} = K_{2} + W_{loss}$

Where:

$K_{1}$ , $K_{2}$ - Initial and final kinetic energy, measured in joules.

$W_{loss}$ - Work losses due to friction.

By applying definitions of kinetic energy and work, the expression described above is expanded:

$\frac{1}{2}\cdot m \cdot v_{1}^{2} = \frac{1}{2}\cdot m \cdot v_{2}^{2} + f \cdot \Delta s$

Where:

$v_{1}$ , $v_{2}$ - Initial and final speed of the skater, measured in meters per second.

$m$ - Mass of the skater, measured in kilograms.

$\Delta s$ - Length of the rough patch, measured in meters.

$f$ - Friction force, measured in newtons.

According to the statement, friction force is represented by the following expression:

$f = r \cdot m \cdot g$

Where:

$r$ - Ratio of friction force to weight, dimensionless.

$g$ - Gravitational constant, measured in meters per square second.

Then,

$\frac{1}{2}\cdot m \cdot v_{1}^{2} = \frac{1}{2}\cdot m \cdot v_{2}^{2} + r \cdot m \cdot g \cdot \Delta s$

The equation is simplified algebraically and patch length is cleared afterwards:

$\frac{1}{2}\cdot (v_{1}^{2}-v_{2}^{2}) = r \cdot g \cdot \Delta s$

$\Delta s = \frac{v_{1}^{2}-v_{2}^{2}}{2 \cdot r \cdot g }$

Given that $v_{1} = 5\,\frac{m}{s}$ , $v_{2} = 2.5\,\frac{m}{s}$ , $r = 0.22$ and $g = 9.807 \,\frac{m}{s^{2}}$ , the length of the rough patch is:

$\Delta s = \frac{\left(5\,\frac{m}{s} \right)^{2}-\left(2.5\,\frac{m}{s} \right)^{2}}{2\cdot (0.22)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}$

$\Delta s = 4.345\,m$

The length of the rough patch is 4.345 meters.

6 0

3 years ago

Convert 1 mm to meters using scientific notation. Include units in your answer.

irinina [24]

Answer: The answer in scientific notation with the unit included is (1 × 10^-3m.)

Explanation:

In the field of physics, when working with too large or too small numbers, such can be expressed with the use of scientific notation. This helps to eliminate huge or ambiguous numbers with significant units. It is written is such a way that the first number is greater than or equal to 1 and less than 10 which is then multiplied by a factor of 10.

Units are symbols that are used to represent a measurement For example the unit of meters is (m).

Converting 1mm to m:

1000millimeters = 1meter

1 millimetre = X

Making X the subject of formula,

X = 1 ×1 /1000

X = 0.001m

Therefore expressing X in scientific notation is

1 × 10^-3meter (m)

7 0

3 years ago

The Grinch is trying to push a 5000-kg sled up the side of Mount Crumpit (whose side make an angle of 60 degrees above the horiz

navik [9.2K]

Answer:

Explanation:

height lost h = 300 sin60

= 259.8 m .

gravitational potential energy = mgh

= 5000 x 9.8 x 259.8

= 1273 x 10⁴ J

Kinetic energy

= 1/2 mv²

= .5 x 5000 x 60²

= 900 x 10⁴ J

there is loss of kinetic energy = 373 x 10⁴ J.

This loss in energy is due to kinetic friction that came into action when the sled slipped downwards.

The lost energy is converted into heat energy or thermal energy.

8 0

4 years ago

A set of pulleys is used to lift a piano weighing 1,000 newtons. The piano is lifted 3 meters in 120 seconds. How much power was

Sergio039 [100]

Answer:

25 watts

Explanation:

Power=work/time

work=force x distance

1000 × 3

=3000 Joules

power= 3000/120

=25 watts

4 0

4 years ago

Consider a system consisting of an ideal gas confined within a container, one wall of which is a movable piston. Energy can be a

Helen [10]

Complete Question

Consider a system consisting of an ideal gas confined within a container, one wall of which is a movable piston. Energy can be added to the gas in the form of heat by applying a flame to the outside of the container. Conversely, energy can also be removed from the gas in the form of heat by immersing the container in ice water. Energy can be added to the system in the form of work by pushing the piston in, thereby compressing the gas. Conversely, if the gas pushes the piston out, thereby pushing some atmosphere aside, the internal energy of the gas is reduced by the amount of work done.

$pV=nRT$

so the absolute temperature T is directly proportional to the product of the absolute pressure p and the volume V,Here n denotes the amount of gas moles,which is a constant because the gas is confined and R is the universal constant

What is the $\triangle U$ as the system of ideal gas goes from point A to point B on the graph recall u is proportional to T