Explanation:
(a) Displacement of an object is the shortest path covered by it.
In this problem, a student is biking to school. She travels 0.7 km north, then realizes something has fallen out of her bag. She travels 0.3 km south to retrieve her item. She then travels 0.4 mi north to arrive at school.
0.4 miles = 0.64 km
displacement = 0.7-0.3+0.64 = 1.04 km
(b) Average velocity = total displacement/total time
t = 15 min = 0.25 hour
Hence, this is the required solution.
Answer:
10m/s
Explanation:
using the formula a=v-u
t
Answer:
Part(a): The frequency is .
Part(b): The speed of the wave is .
Explanation:
Given:
The distance between the crests of the wave, .
The time required for the wave to laps against the pier,
The distance between any two crests of a wave is known as the wavelength of the wave. So the wavelength of the wave is .
Also, the time required for the wave for each laps is the time period of oscillation and it is given by .
Part(a):
The relation between the frequency and time period is given by
Substituting the value of in equation (1), we have
Part(b):
The relation between the velocity of a wave to its frequency is given by
Substituting the value of and
in equation (2), we have