Answer:
Ca.
Sb.
Explanation:
a. When comparing the two elements Ca and As , the more metallic element is:__________ based on periodic trends alone.
The correct option is Ca. Ca belongs to group 2 which is more easily give off it's electrons, compared to As which is a group 5 member.
c. When comparing the two elements Sb and Pb , the more metallic element is:___________ based on periodic trends alone.
The correct option here is Pb. Thhs is because ionization energy decreases down the group. Pb has a lower ionization enthalpy than Sb
Answer:
235/92U+10n→144/54Xe+90/38Sr+2/10n
Explanation:
- The nuclear reaction for the neutron-induced fission of u−235 to form xe−144 and sr−90 is represented by;
235/92U+10n→144/54Xe+90/38Sr+2/10n
- In nuclear fission reactions a heavy nuclide is split into two light nuclides and is coupled by the release of energy.
<span>C<span>l2</span>CHC<span>H2</span>OH<ClC<span>H2</span>C<span>H2</span>OH<C<span>H3</span>C<span>H2</span>OH</span>
These are 9 questions and 9 aswers.
1) Fill in the coefficients that will balance the following reaction:<span>
A₀ Hg(CO₃)₂ + A₁ AgCl → A₂HgCl₄ + A₃Ag₂CO₃
Answer:
Balance in Hg ⇒ A₀ = A2
Balance in Ag ⇒ A₁ = 2A₃
Balance is CO₃ ⇒ 2A₀ = A₃
Balance is Cl ⇒A₁ = 4Cl₄
⇒ System of equations:
</span><span><span>A₀ = A2
A₁ = 2A₃
2A₀ = A₃
A₁ = 4A₂</span>
Start by stating A₂ = 1
⇒ A₁ = 4
A₃ = 4/2 = 2
A₀ = 2/2 = 1
Therefore, the resulting balanced reaction is:
</span><span>Hg(CO₃)₂ + 4 AgCl → HgCl₄ + 2 Ag₂CO₃ <-------- answer
2) Fill in the coefficients that will balance the following reaction:
a₀ Fe(HCO₃)₃ + a₁CaO → a₂Fe₂O₃ + a₃Ca(HCO₃)₂
Answer:
Balance in Fe: a₀ = 2a₂
Balance in H: 3a₀ = 2a₃
Balance in C: 3a₀ = 2a₃
Balance in O: 9a₀ = 3a₂ + 6a₃
Balance in Ca: a₁ = a₃
Start with a₃ = 3
⇒ a₀ = 2
a₁ = 3
a₂ = 1
a₃ = 3
Therefore, the resulting balanced equation is:
</span><span>2 Fe(HCO₃)₃ + 3CaO → Fe₂O₃ + 3 Ca(HCO₃)₂ <----------- answer
3) Fill in the coefficients that will balance the following reaction:
a₀C₃H₇OH + a₁O₂ → a₂CO₂ + a₃H₂O
Answer:
Balance in C: 3a₀ = a₂
Balance in H: 8a₀ = 2a₃
Balance in O: a₀ + 2a₁ = 2a₂ + a₃
Start with a₃ = 4 ⇒
a₀ = 1
a₂ = 3
1 + 2 a₁ = 2×3 + 4 ⇒ a₁ = 4,5
to make alll the coefficients integers multiply by 2:
a₃ = 8
a₀ = 2
a₂ = 6
a₁ = 9
Therefore, the resulting balanced chemical equation is:
</span>
<span>
2C₃H₇OH + 9O₂ → 6CO₂ + 8H₂O
4) Fill in the coefficients that will balance the following reaction:
a₀SnSO₄ + a₁KBr → a₂SnBr₂ + a₃K₂SO₄
Answer:
Balance in Sn: a₀ = a₂
Balance in SO₄: a₀ = a₃
Balance in K: a₁ = 2a₃
Balance in Br: a₁ = 2a₂
Start with a₃ = 1 ⇒
a₀ = 1
a₁ = 2
a₂ = 1
Therefore, the resulting balance equation is:
</span>
<span>
SnSO₄ + 2KBr → SnBr₂ + K₂SO₄ <------------ answer
5) Fill in the coefficients that will balance the following reaction:
a₀NH4Cl + a₁Ag3PO4 → a₂AgCl + a₃(NH4)3PO4
a₂ = 3
a₁ = 1
a₀ = 3
a₃ = 1
⇒ </span><span>3 NH₄Cl + Ag₃PO₄ → 3 AgCl + (NH₄)₃PO₄ <-------- answer
6) Fill in the coefficients that will balance the following reaction:
a₀Cr₂(SO₄)₃ + a₁AgNO₃ → a₂Cr(NO₃)₃ + a₃Ag₂SO₄
Answer:
a₀ = 1
a₁ = 6
a₂ = 2
a₃ = 3
Resulting balanced equation:
</span><span>Cr₂(SO₄)₃ + 6AgNO₃ → 2Cr(NO₃)₃ + 3Ag₂SO₄
7) Fill in the coefficients that will balance the following reaction:
a₀NaC₂H₃O₂ + a₁Fe₂O₃ → a₂Fe(C₂H₃O₂)₃ + a₃Na₂O
Answer:
Balance in Na: a₀ = 2a₃
Balance in </span><span>C₂H₃O₂ : a₀ = 3a₂
Balance in Fe: 2a₁ = a₂
Balance in O: 3a₁ = a₃
Start with a₃ = 3 ⇒
a₁ = 1
a₂ = 2
a₀ = 6
⇒ </span><span>6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O ← answer
8) Fill in the coefficients that will balance the following reaction:
a₀CH₄ + a₁O₂ → a₂CO₂ + a₃H₂O
a₀ = 1
a₁ = 2
a₂ = 1
a₃ = 2
⇒ </span><span>CH₄ + 2O₂ → CO₂ + 2H₂O ← answer
9) Fill in the coefficients that will balance the following reaction:
a₀NaCl + a₁FeO → a₂Na₂O + a₃FeCl₂
Answer:
a₀ = 2
a₁ = 1
a₂ = 1
a₃ = 1
</span>2NaCl + FeO → Na₂O + FeCl₂ ← answer
