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Kaylis [27]
3 years ago
15

Calcium phosphate consists of two ions chemically bonded together. What are charges of each ion?

Chemistry
1 answer:
sdas [7]3 years ago
7 0

Answer: Ca^2+ and P^3-

Explanation:

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A balloon contains 269.7 L of helium at 6.12ºC and 1.00 atm. What is the temperature (in ºC) of the gas if the volume has increa
MatroZZZ [7]

Answer:

T2= 7.3°C

Explanation:

To solve this problem we will use Charles law equation i.e,

V1/T1 = V2/T2    

Given data

V1 = 269.7 L

T1 = 6.12 °C

V2= 320.4 L

T2=?

Solution:

Now we will put the values in equation

269.7 L / 6.12°C  = 320.4 L / T2

T2=  320.4 L × 6.12°C/ 269.7 L

T2= 1960.85 °C. L /269.7 L

T2= 7.3°C

3 0
3 years ago
What does the survival of the fittest mean
Tomtit [17]
It means that the fit and well adjusted ones thrive and "make it", and the weak ones that can't adapt die.
7 0
3 years ago
A centimeter and millimeter differ from each other by a factor of _____ ?
Liono4ka [1.6K]



The answer is:  "10" .
_______________________________________________________________
  " A centimeter and millimeter differ from each other by a factor of "10" .
_______________________________________________________________
Note:
____________________________
100 cm = 1 m


1000 mm = 1m

____________
100 * (10) = 1000 .
_________________
The answer is:  "10".
__________________________________________________________
  " A centimeter and millimeter differ from each other by a factor of "10".
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7 0
3 years ago
2.50 liter of a gas has a pressure of 165. kPa at 25.0°C. If the pressure increases to 600. kPa and the temperature to 100.0°C,
tiny-mole [99]

Answer:

0.861 L

Explanation:

We are given pressure, volume, and temperature, so let's apply the Combined Gas Law:

(P₁V₁)/T₁ = (P₂V₂)/T₂

Convert the temperatures to degrees Kelvin.

25.0°C -> 298 K, 100.0°C -> 373 K

Plug in the initial conditions on the left, then the final/new on the right, and solve for the unknown:

(165(2.5))/298 = (600(V₂))/373

V₂ = (165(2.5)(373))/(298(600))

V₂ = 0.861 L

7 0
3 years ago
How much heat is lost when 0.440 mol of steam condenses at 100 °C?
dusya [7]

Answer:

17,890 J

Explanation:

The amount of heat released by a gaseous substance when it condenses is given by the formula

Q=n\lambda_v

where

n is the number of moles of the substance

\lambda_v is the latent heat of vaporization

The formula can be applied if the substance is at its vaporization temperature.

In this problem, we have:

n = 0.440 mol is the number of moles of steam

\lambda_v=40,660 J/mol is the latent heat of vaporization of water

And the steam is already at 100C, so we can apply the formula:

Q=(0.440)(40660)=17,890 J

8 0
4 years ago
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