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3 years ago

Convection currents in Earth's core transfer heat and material to the surface.

Chemistry

1 answer:

sweet-ann [11.9K]3 years ago

8 0

Answer: False

Explanation: The plate tectonics move due to convection currents of the mantle; the cooler upper mantle descends while the hotter lower mantles ascend. The heat that drives these convection currents emanated from the core of the earth (not the sun).

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What is SI unit of e.m.f and p.d.

xenn [34]

Answer:

Electromotive force or e.m.f is defined as the battery's energy per Coulomb of charge passing through it. like other measures of energy per charge emf has SI unit of volts , equivalent to joules per coulomb.

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3 years ago

Which material cannot be made into a magnet ?

bogdanovich [222]

<span>Its b.aluminum

I hope this helps and sorry if I am wrong </span>

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3 years ago

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What cell part is NOT found in all cells?

elena-s [515]

Answer:

heart I think also I'm so sorry if I get you this wrong I think membrane not sure tell me what was the right answer but I think membrane.

3 0

3 years ago

Why do different molecules require different masses to make 1 mol

Wewaii [24]

Answer:

Different substances have different molecular masses. Thus, equal masses have different numbers of atoms, molecules, or moles. On the other hand, equal numbers of moles of different substances have different masses.

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3 years ago

Given the unbalanced equation below, answer the following: Calculate the number of liters of 3.00 M lead (II) iodide solution pr

mr_godi [17]

The number of liters of 3.00 M lead (II) iodide : 0.277 L

<h3>Further explanation</h3>

Reaction(balanced)

Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)

moles of KI = 1.66

From the equation, mol ratio of KI : PbI₂ = 2 : 1, so mol PbI₂ :

$\tt \dfrac{1}{2}\times 1.66=0.83$

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So the number of liters(V) of 3.00 M lead (II) iodide-PbI₂ (n=0.83, M=3):

$\tt V=\dfrac{n}{M}\\\\V=\dfrac{0.83}{3}\\\\V=0.277~L$

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3 years ago