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german
3 years ago
15

Your answer should have the same number of significant figures as the starting measurement.

Chemistry
1 answer:
OleMash [197]3 years ago
4 0

Answer:

it has two significant figures that is 5 and 1

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When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water according to the r
QveST [7]
The reaction is combination of hydrogen molecules and oxygen molecules and form water. So the oxygen and hydrogen required together is equal to the mass of the water formed.
5 0
4 years ago
Competition occurs when
Katen [24]

Answer:

Competition occurs when <em>(A) two or more organisms need the same resource.</em>

Explanation:

I dont think it could be (B), (C) or (D) because those don't really make sense.

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2 years ago
How many grams can be prepared until equilibrium is attained? carbon disulfide is prepared by heating sulfur and charcoal. the c
e-lub [12.9K]
Kc = [CS2] / [S2][C] but, since C is solid, it doesn't fit here 
<span>Kc = [CS2] / [S2] </span>
<span>S2(g) + C(s) ---> CS2(g) </span>
<span>13.8mole S2 / 6.05L = 2.28M </span>

<span>Kc = x / 2.28-x </span>
<span>9.4 x (2.28-x) = x </span>
<span>21.43 - 9.4x = x </span>
<span>21.42 = 10.4x </span>
<span>x = 2.05M = [CS2] </span>
<span>2.05M x 6.05L = 12.46moles </span>
<span>12.46moles x 76gmole = 946.96g CS2</span>
5 0
3 years ago
What is the heat of vaporization of water?
andrew11 [14]
The molecules in liquid water are held together by relatively strong hydrogen bonds and its enthalpy of vaporization, 40.65 kJ/mol is more than five times the energy required to heat the same quantity of water from: 0 °C to 100 °C (cp = 75.3 J K−1 mol−1).

Hope this helps.
7 0
4 years ago
Red mercury (II) oxide decomposes to form mercury metal and oxygen gas according to the following equation: 2HgO (s) 2Hg (l) + O
diamong [38]

hey there!:

2HgO (s) =>  2Hg (l) + O2 (g)

2 moles of HgO decompose to form 2 moles of Hg and 1 mole of O2 according to the reaction mentioned in the question.

So 4.00 moles of HgO must give 4 moles of Hg and 2 moles of O2 theoretically.

603 g of Hg = 603 / 200.6 = 3 moles

Percent yield = ( actual yield / theoretical yield) * 100

= ( 3/4) * 100

= 75 %

Hope this helps!

7 0
3 years ago
Read 2 more answers
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