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3 years ago

How many total moles of ions are released when 0.0341 moles of Na2HPO4 dissolves completely in water

Chemistry

1 answer:

SSSSS [86.1K]3 years ago

5 0

Answer:

0.1023 moles

Explanation:

We have this reaction

Na2HPO4 → 2Na+ + NPO4-

1 mole gives us 3 ions

Na+ has 2 ions to it

NPO4 has 1 ion

2 + 1 = 3

We multiply 3 with the number of moles to get the answer to this question

3 x 0.0341

= 0.1023 moles

So we conclude that total moles released when dissolved in water is equal to 0.1023

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Answer:

$m_{H_2SO_4}=81.7gH_2SO_4$

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Explanation:

Hello,

Based on the given undergoing chemical reaction is is rewritten below:

$2Al (s) + 3H_2SO_4 (aq)\rightarrow Al _2(SO4)_3 (aq) + 3H_2 (g)$

By stoichiometry we find the minimum mass of H2SO4 (in g) as shown below:

$m_{H_2SO_4}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2SO_4}{2molAl}*\frac{98gH_2SO_4}{1molH_2SO_4} \\m_{H_2SO_4}=81.7gH_2SO_4$

Moreover, mass of H2 gas (in g) would be produced by the complete reaction of the aluminum block turns out:

$m_{H_2}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2}{2molAl}*\frac{2gH_2}{1molH_2} \\m_{H_2}=1.67gH_2$

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A cylinder of compressed gas has a volume of 350 ml and a pressure of 931 torr. What volume in Liters would the gas occupy if al

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Answer:

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