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stealth61 [152]
3 years ago
6

How many total moles of ions are released when 0.0341 moles of Na2HPO4 dissolves completely in water

Chemistry
1 answer:
SSSSS [86.1K]3 years ago
5 0

Answer:

0.1023 moles

Explanation:

We have this reaction

Na2HPO4 → 2Na+ + NPO4-

1 mole gives us 3 ions

Na+ has 2 ions to it

NPO4 has 1 ion

2 + 1 = 3

We multiply 3 with the number of moles to get the answer to this question

3 x 0.0341

= 0.1023 moles

So we conclude that total moles released when dissolved in water is equal to 0.1023

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juin [17]

Answer:

Laboratory acids are far too dangerous to taste, but you will have swallowed some dilute weak acids. Acids have a sour taste, like vinegar, which contains ethanoic acid, and lemons, which contain citric acid. These are safe to use in food, but they can still hurt if they get into a cut or into your eyes.

Explanation:

They can safely be consumed and do not irritate the skin. However, at greater concentrations weak acids can be harmful. Acids can react violently with water and are harmful in the presence of moisture in the mouth or eyes or in proximity with other aqueous solutions.

hope that helps!

4 0
3 years ago
How many molecules are in 2.00 moles of h2o
Sedaia [141]
1 mole = 6.022×10^23 atoms. 1 water molecule = 2 Hydrogen atoms + 1 oxygen atom. So, 1 mole H2O = 1.2044×10^24 hydrogen atoms. Therefore 2 mole H2O will have 2.4088×10^24 hydrogen atoms.
8 0
3 years ago
The formula for the nitrate ion: NO3 NO2 NO3+​
tekilochka [14]

Answer:

NO3-

Explanation:

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3 0
3 years ago
Read 2 more answers
1. Addition of which of the following will increase the solubility of CaCO3 in water? Consider the equilibrium process:
kolbaska11 [484]

Answer: HCl

Explanation:

calcium carbonate dissolves in HCl acid producing CO 2 gas. It will not dissolve in pure water. The Ksp for calcium carbonate in water is 3.4 x 10-9 moldm-3 which is very low. What takes place here is actually a chemical reaction:

CaCO 3 (s) + 2HCl(aq) → CaCl 2 (aq) + H 2CO 3(aq)

This reaction accounts for the solubility of the Calcium carbonate in HCl and not in pure water.

6 0
3 years ago
How many uL are present in 250 mL of H20? (1 uL = 10^-6 Liters)​
Vanyuwa [196]

Answer:

250000 μL

Explanation:

If         1 L = 1000 mL

Then  X L = 250 mL

X = (1 × 250) / 1000 = 0.25 L

Now we can calculate the number of microliters (μL) in 0.25 L:

if        1 μL = 10⁻⁶ L

then   X μL = 0.25 L

X = (1 × 0.25) / 10⁻⁶  =250000 μL

4 0
3 years ago
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