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EastWind [94]
3 years ago
15

Describe the results of Ernest Rutherford's gold-foil experiment and explain how his results changed ideas about the distributio

n of positive charge within the atom.
Chemistry
2 answers:
alina1380 [7]3 years ago
6 0
Ernest Rutherford applies alpha particle towards an atom, some atom showed deflection by smaller angle, very few through large angle and many just passed without any deflection.

His results changed the idea for distribution of positive charges as he concluded almost all the positive charge is in center of the atom (inside nucleus) and it is very heavy than electrons which revolves outside the nucleus

Hope this helps!
sashaice [31]3 years ago
4 0
Physicist Ernest Rutherford<span> established the nuclear theory of the atom with his </span>gold-foil experiment<span>. When he shot a beam of alpha particles at a sheet of </span>gold foil<span>, a few of the particles were deflected. He concluded that a tiny, dense nucleus was causing the deflections.</span>
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Is a stick of dynamite potential energetic or kinetic
qwelly [4]

Answer:Potential Energy

Explanation:

It is because a stick dynamite is a stored energy which have to be acted upon(lighting it) for it to explode

3 0
3 years ago
Read 2 more answers
Calculate the molarity of 65.3 grams of sugar(342.3 g/mol), c12h22011 in 750 ml of solution.
k0ka [10]

Answer:

0.254 M

Explanation:

If the formula mass of sugar is 342.3 g/mol, and there are 65.3 g, then there are 65.3/342.3=0.190768 mol.

Also, 750 mL = 0.750 L.

molarity = (moles of solute)/(liters of solution)

molarity = 0.190768/0.750 = <u>0.254</u><u> </u><u>M</u>

8 0
2 years ago
Complete the chart. (Remember to enter a 0 if necessary.)
Trava [24]
<span>Atomic Number 10 is Neon.

1s: 2
2s: 2
2p: 6 
3s: 0 
3p: 0 
4s: 0
3d: 0
4p: 0 
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6 0
3 years ago
7g of gold is heated from 17 degrees C to 42 degrees C. How much energy (heat) was used? The specific heat capacity of gold is .
wel
Heat needed=mcθ
=7×0.031×(42-17)
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7 0
3 years ago
A solution is prepared by dissolving 0.23 mol of chloroacetic acid and 0.27 mol of sodium chloroacetate in water sufficient to y
Sergio [31]

Answer:

c. chloroacetate ion

Explanation:

The chloroacetic acid, ClCH₂CO₂H, is a weak acid with Ka = 1.36x10⁻³. When this weak acid is in solution with its conjugate base, ClCH₂CO₂⁻ (From sodium chloroacetate) a buffer is produced. The addition of a strong acid as the HCl produce the following reaction

HCl + ClCH₂CO₂⁻ → ClCH₂CO₂H + Cl⁻.

Where the acid reacts with the chloroacetate ion to produce more chloroacetic acid

That means, the HCl reacts with the chloroacetate ion present in the buffer solution

Right answer is:

<h3>c. chloroacetate ion</h3>
8 0
3 years ago
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