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EastWind [94]
3 years ago
15

Describe the results of Ernest Rutherford's gold-foil experiment and explain how his results changed ideas about the distributio

n of positive charge within the atom.
Chemistry
2 answers:
alina1380 [7]3 years ago
6 0
Ernest Rutherford applies alpha particle towards an atom, some atom showed deflection by smaller angle, very few through large angle and many just passed without any deflection.

His results changed the idea for distribution of positive charges as he concluded almost all the positive charge is in center of the atom (inside nucleus) and it is very heavy than electrons which revolves outside the nucleus

Hope this helps!
sashaice [31]3 years ago
4 0
Physicist Ernest Rutherford<span> established the nuclear theory of the atom with his </span>gold-foil experiment<span>. When he shot a beam of alpha particles at a sheet of </span>gold foil<span>, a few of the particles were deflected. He concluded that a tiny, dense nucleus was causing the deflections.</span>
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What is the control center or “brain” of a cell called?
aksik [14]

Answer: The nucleus is often referred to as the control center, or brain, of the cell and contains the DNA, or genetic material. The nucleus is surrounded by the nuclear envelope. ... Human cells are eukaryotic cells.

Explanation:

6 0
3 years ago
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A rigid cylinder with a movable piston contains a sample of hydrogen gas. At 330. K, this sample has a pressure of 150. kPa and
Marta_Voda [28]

Answer:

V₂ = 4.34 L

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 3.50 L

Initial pressure = 150 Kpa (150/101.325 = 1.5 atm)

Initial temperature = 330 K

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ =  1.5 atm ×  3.50 L × 273 K / 330 K × 1 atm

V₂ = 1433.3 atm .L. K / 330 k.atm

V₂ = 4.34 L

4 0
3 years ago
when a log of wood burns, it undergoes a _______. a. physical change. b. chemical change. c. physical and a chemical change. d.
statuscvo [17]
B. Chemical change is the answer!<span />
3 0
2 years ago
Read 2 more answers
What is the value of the equilibrium constant for this redox reaction?
aivan3 [116]
Correct  answer: Option D, <span>K = 5.04 × 10^52
</span>
Reason:
We know that, 
Ecell = \frac{0.0592}{n}log(K),
where n = number of electrons = 2 (in present case)
K = equilibrium constant.

Also, Ecell = <span>+1.56 v

Therefore, 1.56 = </span>\frac{0.0592}{2}log(K)
Therefore, log (K) = 52.703
Therefore,  K = 5.04 X 10^52


8 0
3 years ago
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A TLC plate showed 2 spots with Rf values of 0.25 and 0.26. The plate was removed from the developing chamber, the residual solv
Katena32 [7]

Answer:

See explanation

Explanation:

TLC is a chromatographic method in which the solute is spotted on a plate and the plate is placed in an air tight chamber containing a solvent. The solvent is maintained below the level of the spot. The capillary movement of the solvent through the plate achieves the required separation.

If two spots have Rf values of 0.25 and 0.26 respectively and then the plate was removed from the developing chamber, subsequently, the residual solvent was allowed to evaporate from the plate, and then the plate was returned to the developing chamber.

It will be observed after the second development is complete that the new Rf values will be 0.50 and 0.52 respectively. It will just be as though the second chromatogram picked up from where the first chromatogram stopped.

4 0
2 years ago
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